The diagonal is 8.602 cm
The diagonal is 3.61cm
Perimeter of Rectangle = 2(length + width) =2(45+30) =150 cm
Length of rectangle: 7.9 cm Width of rectangle: 1.3 cm Area of rectangle: 7.9 times 1.3 = 10.27 square cm
The width is 6 cm and the length is 12 cm.
15 cm for the diagonal.
The diagonal is 3.61cm
Width would be 14 cm
The length is 20 cm.
62 +82 = 102 so 6 and 8
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
In order to find the diagonal the length and width of the rectangle must be found first so let the length be x and the width be (x-4.2) length*width = area x*(x-4.2) = 211.68 Multiply out the brackets and subtract 211.68 from both sides thus forming a quadratic equation: x2-4.2-211.68 = 0 Solving the above equation by means of the quadratic formula gives a positive value of 16.8 for x Therefore: length = 16.8 cm and width = 12.6 cm Use Pythagoras to find the rectangle's diagonal: 16.82+12.62 = 441 and the square root of this is 21 Therefore the diagonal of the rectangle is 21 cm
15 cm Solved through Pythagoras' theorem.
width=9 length=18
the width equals 14 cm. and the length equals 31 cm.
The length of the diagonal of a rectangle with adjacent sides measuring 820cm and 1200cm is about 1453.4cm
The area of a rectangle is: length * width= 45 cm * 30 cm = 1350 cm^2
To find the length of a rectangle, you can use the formula for area: Area = Length × Width. Given that the area is 96 cm² and the width is 8 cm, you can rearrange the formula to find the length: Length = Area ÷ Width. Thus, Length = 96 cm² ÷ 8 cm = 12 cm. Therefore, the length of the rectangle is 12 cm.