The diagonal of a 30' x 30' square is: 42.43 feet.
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
Well, isn't that a happy little question! To find the diagonal measurement of a square, we can use the Pythagorean theorem. So, for a square that is 16 feet by 24 feet, we can calculate the diagonal by taking the square root of (16^2 + 24^2), which equals about 28.84 feet. Just imagine that diagonal stretching across your square canvas, creating a beautiful harmony of length and width.
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, both sides of the square are 36 feet long, so the diagonal can be calculated as √(36^2 + 36^2) = √(1296 + 1296) = √2592 ≈ 50.91 feet. Therefore, the diagonal measurement of a 36-foot by 36-foot square is approximately 50.91 feet.
About 8.5 feet.
The diagonal of a 30' x 30' square is: 42.43 feet.
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
The diagonal of a 46' x 46' square is 65.05 feet.
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
About 28.28 feet.
Area of Rhombus = length of first diagonal x length of second diagonal / 2 / means divided by So for your problem: Area of Rhombus = 10 feet x 14 feet / 2 = 70 square feet
Well, isn't that a happy little question! To find the diagonal measurement of a square, we can use the Pythagorean theorem. So, for a square that is 16 feet by 24 feet, we can calculate the diagonal by taking the square root of (16^2 + 24^2), which equals about 28.84 feet. Just imagine that diagonal stretching across your square canvas, creating a beautiful harmony of length and width.
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, both sides of the square are 36 feet long, so the diagonal can be calculated as √(36^2 + 36^2) = √(1296 + 1296) = √2592 ≈ 50.91 feet. Therefore, the diagonal measurement of a 36-foot by 36-foot square is approximately 50.91 feet.
Using Pythagoras: 10 times square root of 2 feet
Ah, what a lovely question! To find the diagonal measurement of a square, we can use the Pythagorean theorem. So, for a square that is 24 feet by 24 feet, we can use the formula diagonal = √(side length squared + side length squared). Plugging in the values, we get diagonal = √(24^2 + 24^2) = √(576 + 576) = √1152 ≈ 33.94 feet.
The radius of a square is the radius of the circumcircle, ie the distance from the centre of the square to any vertex, which is half the length of the diagonal of the square. Using Pythagoras: diagonal^2 = side^2 + side^2 → diagonal = √(2 x side^2) area = side^2 → diagonal = √(2 x area) radius = 1/2 x diagonal = 1/2 x √(2 x area) → radius = 1/2 x √(2 x 72 sq in) = 1/2 x √(144 sq in) = 1/2 x 12 in = 6 in.
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)