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Using Pythagoras: 10 Times Square root of 2 feet

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What is the perimeter of a rectangle with a side that is 8 feet long and a diagonal that is 10 feet long?

The diagonal is 10 feet. The one side is 8 feet and the other side is 6 feet (by Pythagoras 82 + 62 = 102)). The perimeter is thus 28 feet.


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Approximately 15.62 feet.


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Assuming you are talking about a rectangular area, the diagonal would be found using the Pythagorean Theorem. 5^2 + 10^2 = d^2, so 125 = d^2, then take square root of both sides. This means the diagonal is approximately 11.18 feet. It is exactly 5√5 feet.


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How many square feet in a 10 feet by 10 feet room?

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What is the diagonal length of a table that is 10ft by 12ft?

To find the diagonal length of a rectangular table, you can use the Pythagorean theorem. For a table measuring 10 feet by 12 feet, the diagonal (d) can be calculated using the formula (d = \sqrt{(10^2 + 12^2)}). This gives (d = \sqrt{(100 + 144)} = \sqrt{244}), which is approximately 15.62 feet.


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How many square feet is a room 10 feet by 10 feet?

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How many square feet ina 10x10 feet room?

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