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Using Pythagoras: 10 Times Square root of 2 feet

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Q: What is the feet across diagonal of a 10 x 10 ft room?
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What is the perimeter of a rectangle with a side that is 8 feet long and a diagonal that is 10 feet long?

The diagonal is 10 feet. The one side is 8 feet and the other side is 6 feet (by Pythagoras 82 + 62 = 102)). The perimeter is thus 28 feet.


What is the length of diagonal line in a rectangle 12 feet long and 10 feet wide?

Approximately 15.62 feet.


What is the diagonal of a 5 feet by 10 feet area?

Assuming you are talking about a rectangular area, the diagonal would be found using the Pythagorean Theorem. 5^2 + 10^2 = d^2, so 125 = d^2, then take square root of both sides. This means the diagonal is approximately 11.18 feet. It is exactly 5√5 feet.


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How many square feet in a 10 feet by 10 feet room?

10' x 10' = 100'2


How many square feet are there in a room that measures 10 feet by 10 feet?

10 X 10 = 100


What is the diagonal of a 10 x 10 box?

A box is a 3-dimensional object and only two measures are given so it is not clear what the question means. Across the base of the box, the diagonal is 10*sqrt(2) = 14.142 approx.


How many square feet is a room 10 feet by 10 feet?

100 sq. ft.


How big is a room that is 110 square feet?

A room that is 110 square feet typically measures about 10 feet by 11 feet.


What is the area of a rhombuswith diagorasls of10 feet and 14feet?

Area of Rhombus = length of first diagonal x length of second diagonal / 2 / means divided by So for your problem: Area of Rhombus = 10 feet x 14 feet / 2 = 70 square feet


How many square feet ina 10x10 feet room?

10 feet*10 feet=100 square feet