d=x√2
where d is a diagonal and x is a side
d=80√2 (or 113.137)
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By the Pythagorean theorem, the diagonal length of a square with a side length of 80 units is √[2(80)2] = 80√2 units.
The diagonal of a square is not perpendicular to its side. The diagonal of a square will separate the square into two triangles. The diagonal goes from one corner to the opposite corner. Because it is a square, the diagonal and a side of the square will always form a 45-degree angle.
To find the area of a square with a diagonal of 14, we first need to determine the length of one side of the square. Using the Pythagorean theorem, we can calculate that the side length is 7√2. Then, we can find the area of the square by squaring the side length, which gives us 98 square units.
Not always, the diagonal can be figured out using the Pythagorean Theorem (a²+b²=c²). Where the diagonal is the hypotenuse (c). By rearranging the Pythagorean Theorem, you can see that the diagonal of a square is always 1.4 times the side of the square.
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49
18 ft Diagonal of a square is the square root of 2, times the side.