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d=x√2

where d is a diagonal and x is a side

d=80√2 (or 113.137)

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Diana Obertas

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3y ago
This answer is:
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Marielle Hane

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3y ago
great answer, tyyy!
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Myra Bradtke

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3y ago
idk if youre right
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Wiki User

11y ago

By the Pythagorean theorem, the diagonal length of a square with a side length of 80 units is √[2(80)2] = 80√2 units.

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Q: What is the diagonal of square with a side of 80?
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How is the length of a diagonal of a square found?

As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.


Is a diagonal of a square perpendicular to its side always?

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How do you find the side of a square if you know its diagonal?

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Not always, the diagonal can be figured out using the Pythagorean Theorem (a²+b²=c²). Where the diagonal is the hypotenuse (c). By rearranging the Pythagorean Theorem, you can see that the diagonal of a square is always 1.4 times the side of the square.


What is the diagonal of 11 square inches?

As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in


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