y=2x+13
y = 2x - 1
It is: y = 2x-6
Well. Slope intercept is y= mx + b. With B being the y intercept. If it contains 1,1 and the slope is positive 6, do the equation 1 = 6 (1) + b. 1 = 6 + b -5 = b. So the answer is y = 6x - 5
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Slope: -3 Point: (4, -5) Equation: y = -3x+7
y=2x+1
y=3x-3
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
The answe iss..... 6
y=2x+1
y = 2x - 1
It is: y = 2x-6
no it is different
y-9 = 3(x-4) y = 3x-3 in slope intercept form
Well. Slope intercept is y= mx + b. With B being the y intercept. If it contains 1,1 and the slope is positive 6, do the equation 1 = 6 (1) + b. 1 = 6 + b -5 = b. So the answer is y = 6x - 5