Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2.
Two straight lines are perpendicular if the product of their gradients is -1.
Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5
The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3
The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15
negative 1
If you mean: y = 3/4x-0.5 then the perpendicular equation could be y = -4/3x-5
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
5
Known equation: y = 2x+10 Perpendicular equation: 2y = -x+10 Both equations intersect at: (-2, 6) Distance from (2, 4) to (-2, 6) is sq rt of 20 using the distance formula
y = - 1/3 x + any number.
y=-x
y equals -1/3x plus 4/3
It would be perpendicular to a line with the equation Y = 1/8 X.
y = 1/3x+4/3
"Y = any number" is perpendicular to "x = -3".
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
It could be y = -x+5
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
6
0909
It could be y = -2/3x+5