The equation is: (x+3)^2 +(y+5)^2 = 16
If you mean: (x+5)^2 + (y+3)^2 = 16 Then its center is at (-5, -3) and its radius is 4
It is: (x+3)^2 + (y+5)^2 = 36
Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
center 5,-3 radius 4
The equation is: (x+3)^2 +(y+5)^2 = 16
The equation is: (x+1)^2 +(y+5)^2 = 36
If you mean: (x+5)^2 + (y+3)^2 = 16 Then its center is at (-5, -3) and its radius is 4
If you mean: (x+9)^2 + (y+5)^2 = 64 Then the center of the circle is at (-9,-5) and the radius is 8
The equation of a circle can be written in the form (x-h)2 + (y - k)2 = r2, where r is the radius, and (h,k) is the center. So for your example, the equation would be: (x- 5)2 + (y - 3)2 = 72
It is: (x+3)^2 + (y+5)^2 = 36
It is (x - 1)^2 + (y - 1)^2 = 5^2
(x + 3)2 + (y + 5)2 = 36
(x - 9)2 + (y + 5)2 = 16
(x + 1)2 + (y + 5)2 = 36
(x+3)2 + (y-5)2 = 9