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What is the diagonal measurement of 40' X 50'?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 50' rectangle can be calculated as follows: diagonal = √(40^2 + 50^2) = √(1600 + 2500) = √4100 ≈ 64.03 feet.
How do you find the diameter of a rectangle?
a swimming pool is 60 ft x 170 ft x 40 ft x 150 ft; what is the distance to swim across the pool from one corner to the other corner?
The length of a rectangle is four times its width. If the perimeter of the rectangle is 60 inches. What is the area of the rectangle?
Let the length be 4x and the width be x: 2(4x+x) = 60 8x+2x = 60 10x = 60 x = 6 So: length = 24 and width = 6 Area = length*width Area = 144 square inches
If the length of a rectangle is 4yards longer than the width and the perimeter is 40 yards what is the area?
let x=length of rectangle let y=width of rectangle x=y+5 2x+2y=40 2(y+5)+2y=40 2y+10+2y=40 4y+10=40 4y=30 4y=7.5 x=7.5+5 x=12.5 AREA: 12.5 x 7.5 = 93.75 YARDS
The length of a rectangle is twice its width If the perimeter of the rectangle is 60cm find its area?
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
