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What is the diagonal measurement of a rectangle measuring 24 feet by 40 feet?
46.648 ft
If you know both the perimeter an the length of a rectangle how can you determine the width of the rectangle?
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
What is width of rectangle with length 40 meters and perimeter 120 meters?
To find the perimeter of the rectangle you add up all the sides. There are two lengths and widths for every rectangle, so you know the length is 40 meters x 2 = 80 meters. Perimeter is the total length of all the sides so you just minus 120 from the two lengths which is 80. So the width is 40, divide 2 (2 widths) = 20 meters. Width = 20 meters OR if they're asking for widthS then it'll be 40 meters, but they're not.
How do I find the width of a rectangle if I know its length and its perimeter?
To find the width of a rectangle, multiply the lenght by 2 and subtract it from the perimeter. Once this is done you are left with the two width sides of the rectangle. To find the width divide this number by 2 and you have your answer. For exaple: P= 120 cm L= 40 cm L* 2 = 80 120 - 80 = 40 40/2 = 20 W=20
If the area of a rectangle is 40 square inches and the length is 6 inches more than the width what is the length and the width of the rectangle?
(6 + w) = length w = width (6 + w)(w) = 40 square inches w squared + 6w = 40 w = 4 inches and the length must be equal to 10 inches
What is the diagonal measurement of 40' X 50'?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 50' rectangle can be calculated as follows: diagonal = √(40^2 + 50^2) = √(1600 + 2500) = √4100 ≈ 64.03 feet.
What is the diagonal measurement of 40 and 30?
Assuming that the 40 and 30 refer to sides of a rectangle and not to any of the infinite number of other possible shapes, the answer is 50.
What is the length of one diagonal if the base a measure 16 and the base b is 24 and has the area of 40 and a ratio of 2 is to 3?
If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal
What is the area of a rectangle if the width is 8in on both sides and the length is 5in on both sides?
The area of a rectangle = length x width = 5 x 8 = 40 square inches.
How long is the diagonal dimension of a rectangle with dimensions of 26' 40 '?
The diagonal is 47.707'
What is the diagonal of a 40 x 100 rectangle?
116
What is the sum of the length of the diagonals of a 12 by 16 rectangle?
If the length of a rectangle is 12 and the width of the rectangle is 16, by the Pythagorean theorem we know that one diagonal is 20 units long. You can draw two diagonals within a rectangle, so the length of both diagonals together is 20+20 = 40 units.
What is the diagonal measurement of 40' x 60'?
To find the diagonal measurement of a rectangle, we can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) of a right triangle is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 60' rectangle can be calculated as follows: Diagonal = √(40^2 + 60^2) = √(1600 + 3600) = √5200 ≈ 72.11 feet. Therefore, the diagonal measurement of a 40' x 60' rectangle is approximately 72.11 feet.
What is The Perimeter if The Length was 40 and The Width was 10?
If you're talking about a rectangle, then the answer is 100. There are 2 sides that have 40 as the length, and double that length is 80. There are 2 sides that have 10 as the width, and double that width is 20. 80 + 20 = 100.
If the length of a rectangle is 6 in and the width is 14 in what is the perimiter?
The answer is 40 (cm?). 6 + 6 (both sides) +14+14= 40
The diagonal of rectangle is 50 cm its breadth is 30 cm then the perimeter is?
Using Pythagoras theorem its length is 40 cm and so 2(40+30) = 140 cm which is its perimeter
What is the perimeter a the rectangle18 feet 40 feet?
The distance around or Perimeter of a Rectangle is equal to the sum of the length of the 4 sides.18' + 40' + 18' + 40' = 116'
