To find the diagonal measurement of a rectangle, we can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) of a right triangle is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 60' rectangle can be calculated as follows:
Diagonal = √(40^2 + 60^2) = √(1600 + 3600) = √5200 ≈ 72.11 feet.
Therefore, the diagonal measurement of a 40' x 60' rectangle is approximately 72.11 feet.
32.311
60 x 40 = 2400 40 x 60 = 2400 4800 / 100 = 48
60+40+55+x=360 x=205
60*40*1=2400 ft**3 of sand
x=100
42
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
Diagonal = 36.9 feet
The diagonal of a 12' x 24' rectangle is approx 26.8'.
17.8885'
32.311
The diagonal of the paver is about 848.53mm
14.42 feet.
The diagonal is 20.
116
That would be 34 feet.
using the Pythagorean theorem, you take 60^2 + 40^2 = X^2 to get 3600 + 1600 which equals 5200, then you take the sq root of that which gives you approx 72.111