14 cm^3 (14+14+1+1=30 and 14*1=14cm^3)
what is the value of x so that the perimeter of the rectangle shown is at least 92 centimeters
L + W >= 24, L = W + 4, Possible dimensions 14 and 10 giving an area of 140 sq cm.
rectangle with 10" length and 2x-4 width 60" area
5.5 inches
yoyoyoyyoyo gamers na fam
what is the value of x so that the perimeter of the rectangle shown is at least 92 centimeters
52 ft
52 (13•4)
If we restrict ourselves to whole numbers, then 1 x 14 will have the least possible area.
square
7 x 19 cm
For a fixed perimeter, the area will always be the same, regardless of how you describe the rectangle.
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
47
Assuming no fractional dimensions, least possible area would be a rectangle measuring 1cm x 9cm. Area increases to a maximum of 25 sq cm when shape is square, ie 5cm x 5cm.
0.000...1cm length on two sides. 19.999...9cm length on the other two.
16 and 12