n * (n - 1) / 2
That would ignore the "acyclic" part of the question. An acyclic graph with the maximum number of edges is a tree. The correct answer is n-1 edges.
There is no limit to the number of vertices that a solid can have.There is no limit to the number of vertices that a solid can have.There is no limit to the number of vertices that a solid can have.There is no limit to the number of vertices that a solid can have.
Yes, polygons have the same number of sides and vertices.
Add one to a hexagons number of vertices
If the number of vertices is not the same as the number of faces, it cannot be a pyramid.
There is no limit to the number of vertices nor edges.
n - 1
n-1
V*(V-1)/2
Given an undirected graph G=(V,E) and an integer k, find induced subgraph H=(U,F) of G of maximum size (maximum in terms of the number of vertices) such that all vertices of H have degree at least k
It is a true statement.
In a Directed Acyclic Graph (DAG), the longest path is the path with the greatest number of edges between two vertices, without forming a cycle.
The term "cyclic graph" is not well-defined. If you mean a graph that is not acyclic, then the answer is 3. That would be the union of a complete graph on 3 vertices and any number of isolated vertices. If you mean a graph that is (isomorphic to) a cycle, then the answer is n. If you are really asking the maximum number of edges, then that would be the triangle numbers such as n (n-1) /2.
Every prism has vertices. They have an even number of vertices, with a minimum of 6 and no maximum.
The expression "acyclic number" is not recognised: additional context may help.
Six.
I believe that such an object cannot exist in normal 3-d space. If there are 6 vertices, the maximum number of edges is 12.
Let G be a complete graph with n vertices. Consider the case where n=2. With only 2 vertices it is clear that there will only be one edge. Now add one more vertex to get n = 3. We must now add edges between the two old vertices and the new one for a total of 3 vertices. We see that adding a vertex to a graph with n vertices gives us n more edges. We get the following sequence Edges on a graph with n vertices: 0+1+2+3+4+5+...+n-1. Adding this to itself and dividing by two yields the following formula for the number of edges on a complete graph with n vertices: n(n-1)/2.