The perimeter of a rectangle with dimensions of 8 X 6 is 28 units.
To find the perimeter, you use the formula: 2l+2w, where l is the length and w is the width.
In your case, the formula would read: 2(8) + 2(6) = 16 + 12 = 28
1.5 by 2
The width of the rectangle is 8. 48/6 = 8
If the given dimensions are that of a rectangle then perimeter is: 34 feet
The dimensions given are not that of a rectangle but are probably that of an isosceles trapezoid in which case it is:- Area = 0.5*(8+10)*2 = 18 square feet
12cm
1.5 by 2
The area of rectangle is : 32.0
54
The width of the rectangle is 8. 48/6 = 8
4 x 4 1 x 16
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
If its a rectangle then: 8+8+6+6 = 28 yards
The dimensions are 16 units by 8 units of mearsurement
If the given dimensions are that of a rectangle then perimeter is: 34 feet
Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.
A rectangle is a 2-dimensional object and cannot have a volume. A [rectangular] cuboid, of dimensions 8*12*24 has a volume = 2304 cubic units.
Come on! 88 = 11 x 8, end of story.