A square with a side length of 8 cm has an area of 64 cm2
The area of a square that has a perimeter of 32m is: 64 m2
32
P = 32cm
The square will have an area of 64 sq m while the rectangle will have an area of 63 sq m
8cm * 8cm = 8*8 cm2 = 64 cm2
A square with a side length of 8 cm has an area of 64 cm2
The square's diagonal is 11.314 cm
Each side = 8 metres (32 divided by 4 sides). The area = 8 x 8 = 64 square metres.
That depends on how many sides the figure has. For example . . . -- If it's a triangle, then its area is 27.7 cm2. -- If it's a square, then its area is 64 cm2. -- If it's a pentagon (5 sides), then its area is 110.1 cm2. -- If it's a hexagon (6 sides), then its area is 166.3 cm2. . . etc.
Sorry the options are actually 64 cm2, 16 cm2, 32 cm2, 50 cm2. Thanks
You are asking what the perimeter of a figure is when you already know it. What kind of question is that? I'll assume you mean the area of the square is 64 cm2. The area of a square in calculated by multiplying the width by the length. For a square they are equal to each other. That means each side is 8 cm. There are four sides on a square., so the perimeter (the distance around it) is 4x8 or 32 cm.
Area = 64*64 = 4096 square m
It is: 64*64 = 4096 square m
The cubed root of 64 is 4. (4)2 Four squared is 16. Hope it helped! :3
The length of each side of a square with an area of 64 is: 8.
Area = 64 cm2 so length of side = 8cm Then, by Pythagoras, length of diagonal = sqrt[82 + 82] = 8*sqrt(2) = 11.3137 cm (to 4 dp)