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What is the slope of a line perpendicular to a line that contains the points 0 and 2 and -3 and 4?
Slope: (2-4)/(0--3) = -2/3 Perpendicular slope: 3/2
What is the standard form of the equation of a circle with its center at (2 -3) and passing through the point (-2 0)?
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
What is the distance between the points -2 0 and 5 3?
Let (x1, y1) = (-2, 0) and (x2, y2) = (5, 3). Distance between two points = square root of [(x2 - x1)2 + (y2 - y1)2] = square root of [(5 - -2)2 + (3 - 0)2] = square root of (72 + 32) = square root of 58
How do you work out the solutions for 3x-2y equals 1 and 3x square-2y square plus 5 equals 0?
How to solve: 3x - 2y = 1 3x2 - 2y2 + 5 = 0 Rearrange the first equation to make x or y the subject (that is x = something or y = something) and then substitute into the second equation and solve that: 3x - 2y = 1 => y = (3x - 1)/2 3x2 - 2y2 + 5 = 0 => 3x2 - 2((3x - 1)/2)2 + 5 = 0 [substitute for y] => 3x2 - 2(9x2 - 6x + 1)/4 + 5 = 0 [expand the square term] => 3x2 - (9x2 - 6x + 1)/2 + 5 = 0 [spot that 2w/4 is the same as w/2] => 6x2 - (9x2 - 6x + 1) + 10 = 0 [multiply equation by 2] => 6x2 - 9x2 + 6x - 1 + 10 = 0 [remove the brackets by multiplying by -1 as it is -1 x (..)] => -3x2 + 6x + 9 = 0 [collect together terms] => 3x2 - 6x - 9 = 0 [multiply whole equation by -1] => x2 - 2x - 3 = 0 [divide whole equation by 3] => (x - 3)(x + 1) =0 [factorize) => x = 3 or -1 [as one factor or the other must be zero] Now use first equation to find corresponding y terms: x = 3:y = (3 x (3) - 1) / 2 = 8 / 2 = 4 x = -1: y= (3 x (-1) - 1) /2 = -4 / 2 = -2 So the solution is the (x, y) pairs, or points, (3, 4) and (-1, -2). The answer can be checked using the second equation: (3, 4): 3(3)2 - 2(4)2 + 5 = 3 x 9 - 2 x 16 + 5 = 27 - 32 + 5 = 0 (-1, -2): 3(-1)2 - 2(-2)2 + 5 = 3 x 1 - 2 x 4 + 5 = 3 - 8 + 5 = 0
What ordered pairs is not a solution to the inequality y equals -3X - 2 A. 1. 1 B. 0. -1 C. 0. 0 D. -1. 0?
If y = -3x - 2 then substituting x from each ordered pair gives :- A) (1,1) y = (-3*1) - 2 = -5 ☒ B) (0,-1) y = (-3*0) - 2 = -2 ☒ C) (0,0) y = (-3*0) - 2 = -2 ☒ D) (-1,0) y = (-3*-1) - 2 = 1 ☒ So the answer is ALL OF THEM are not solutions to the equation y = -3x - 2.......BUT, you've used the word Inequality so depending whether y > -3x - 2 or y < -3x -2 clearly affects the results.
What is the range of this relation (2 -3) (-4 2) (6 2) (-5 -3) (-3 0)?
The range is {-3, 2, 0}.
What is the range of this relation(2, -3), (-4, 2), (6, 2), (-5, -3), (-3, 0)?
{-3,2,0}
What is the range of this relation(-3, 2), (2, -4), (2, 6), (-3, -5), (0, -3)?
{2,-4,6,-5,-3}
What is the range of this relation -3 2 2 -4 2 6 -3 -5 0 -3?
1 it is the difference between the highest and lowest number
What is the domain of the relation 2 8 0 8 1 5 1 3 2 3?
The domain of a relation consists of all the unique input values (or first elements) from the ordered pairs. In the given relation, the pairs are (2, 8), (0, 8), (1, 5), (1, 3), and (2, 3). The unique input values are 0, 1, and 2, so the domain of the relation is {0, 1, 2}.
What is the range of 3 3 4 2 1 3 3?
3,3,4,2,1,3,3 3-3=0 range=0
What is the domain of this relation(-3, 2), ( 2, -4), (2, 6), (-3, -5), (0, -3)?
{-3,2,0}
Is this relation a function{(0, 0), (1, 0), (2, 0), (3, 0), (4, 0)}?
yes
What is the range of data with numbers 3 0 3 4 1 6 2 4 3 2 0 3 5?
The range is 6. (6 - 0 = 6)
What is the domain of this relation(2, -3), (-4, 2), (6, 2), (-5, -3), (-3, 0)?
{2,-4,6,-5,-3}
Is the relation (1 3) (4 0) (3 1) (0 4) (2 3) a function?
If those are the only values, no.
What is the range of 0 1 2 3 4 5 6?
The range of {0, 1, 2, 3, 4, 5, 6} is 6 - 0 = 6.
