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If a radius of a circle intersects a chord it is perpendicular to that chord?
False
How do you find the radius of a circle if you know the length of a chord and the shortest distance from the center of the chord to the circle?
Imagine if you will a circle with a chord drawn through it and a line running from the center of that chord to the center of the circle. That line is necessarily perpendicular to the chord. This means you have a right triangle whose hypotenuse is the radius of the circle. The radius is thus given by: r = sqrt{(1/2 chord length)^2 + (length of perpendicular line)^2} The actual formula to find the radius is as follows: r= C squared/8a + a/2, where C is the chord length, and a is the distance from center point of the chord to the circle , and a and C form an angle of 90 degrees. the entire formula before simplification is r = sqrt {(1/2 C)^2 + (r-a)^2}
Is a radius a chord of a circle?
No, but the diameter of a circle is its largest chord
In math how do you found the chord in a circle?
A chord is when two points in a circle are connected by segment. A diameter is a chord, but not a radius. The radius is not a complete segment in the circle
How do you find radius of a circle?
Draw a line from any part on the outside of a circle to the exact center of the circle. * * * * * That is fine if you know where the center is but not much use if you are just given a circle and do not know where the exact centre is. In this case: Draw a chord - a straight line joining any two points on the circumference of the circle. Then draw the perpendicular bisector of the chord. Draw another chord and its perpendicular bisector. The two perpendicular bisectors will meet at the centre.
If a radius of a circle is perpendicular to a chord at what point does it intersect the chord?
The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
If a radius of a circle intersects a chord then it bisects that chord?
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
If a radius of a circle is perpendicular to a chord then it that chord?
Bisects
If a radius of a circle bisects a chord then it is to that chord?
Perpendicular.
A radius of a circle is perpendicular to a chord if and only if?
Bisects that chord
If a radius of a circle intersects a chord it is perpendicular to that chord?
False
What is a line perpendicular to a radius of a circle called?
A Chord. Or another radius!
If a radius of a circle is perpendicular to a chord then it bisects that chord?
YesAt a right angle
True or False If a radius of a circle intersects a chord it is perpendicular to that chord?
its false
True or False if a radius of a circle is perpendicular to a chord then it bisects that chord?
true, because both distances of the chord are congruent
How do you find the radius of a circle if you know the length of a chord and the shortest distance from the center of the chord to the circle?
Imagine if you will a circle with a chord drawn through it and a line running from the center of that chord to the center of the circle. That line is necessarily perpendicular to the chord. This means you have a right triangle whose hypotenuse is the radius of the circle. The radius is thus given by: r = sqrt{(1/2 chord length)^2 + (length of perpendicular line)^2} The actual formula to find the radius is as follows: r= C squared/8a + a/2, where C is the chord length, and a is the distance from center point of the chord to the circle , and a and C form an angle of 90 degrees. the entire formula before simplification is r = sqrt {(1/2 C)^2 + (r-a)^2}
Is a radius a chord of a circle?
No, but the diameter of a circle is its largest chord
