First of all, if the rotation is 180 degrees then there is no difference clockwise and anti-clockwise so the inclusion of clockwise in the question is redundant.
In terms of the coordinate plane, the signs of all coordinates are switched: from + to - and from - to +.
So
(2, 3) becomes (-2, -3),
(-2, 3) becomes (2, -3),
(2, -3) becomes (-2, 3) and
(-2, -3) becomes (2, 3).
Because 180 degrees clockwise is the same as 180 degrees counterclockwise.
A 180° rotation is half a rotation and it doesn't matter if it is clockwise of counter clockwise. When rotating 180° about the origin, the x-coordinate and y-coordinates change sign Thus (1, -6) → (-1, 6) after rotating 180° around the origin.
180 degrees
Oh, dude, it's like you just take the original coordinates and swap them around while changing the sign of one of them. So, for a 180-degree counterclockwise rotation, you just flip the signs of both x and y. Easy peasy lemon squeezy!
360 degrees would be one full rotation. 180 degrees would be a half rotation. 360+180=540 So it would be a rotation and a half.
Because 180 degrees clockwise is the same as 180 degrees counterclockwise.
Fomula(work with both clockwise/counterclockwise):(-x,-y)
The rule for a rotation by 180° about the origin is (x,y)→(−x,−y) .
A 180° rotation is half a rotation and it doesn't matter if it is clockwise of counter clockwise. When rotating 180° about the origin, the x-coordinate and y-coordinates change sign Thus (1, -6) → (-1, 6) after rotating 180° around the origin.
(x, y) -> (-x, -y)
180 degrees
A 180 degree rotation between front and back is normal for US coins.
Oh, dude, it's like you just take the original coordinates and swap them around while changing the sign of one of them. So, for a 180-degree counterclockwise rotation, you just flip the signs of both x and y. Easy peasy lemon squeezy!
It is (-1, 6).Also, if the rotation is 180 degrees, then clockwise or anticlockwise are irrelevant.It is (-1, 6).
(-e, -h)
180 degrees is half a rotation so probably a half.
To find the image of ABC for a 180-degree counterclockwise rotation about point P, we would reflect each point of the triangle across the line passing through P. The resulting image of ABC would be a congruent triangle with its vertices in opposite positions relative to the original triangle.