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What is the image of point (4 3) if the rotation is -180 degrees?
Conventionally positive angles are measured anticlockwise, by 180° is a half turn regardless of direction. It depends where the centre of rotation is, so where would you like the image to be? If the centre is at, say, (4, 3) then the image will be at (4, 3) regardless of the angle of rotation. If the centre is at, say, (4, 4) then the image will be at (4, 5) If the centre is at, say, the origin, ie (0, 0) then the image will be at (-4, -3).
What are the coordinates of the image of the point 2 5 after it is rotated 180 degrees clockwise about the origin?
Rotating it about the origin 180° (either way, it's half a turn) will transform a point with coordinates (x, y) to that with coordinates (-x, -y) Thus (2, 5) → (-2, -5)
Which describes a transformation using rotation?
The centre of rotation, the angle of rotation and, unless the angle is 180 degrees, the direction of rotation.
Andrew and rotation maps point M(9 and ndash1) to M and rsquo( and ndash9 1). Which describes the rotation?
180 rotation
What will you add to 9 to become 6 Except for -3?
A 180 degree rotation?
what is the image of the point (-2,7) after a rotation of 180 counterclockwise about the origin?
The rule for a rotation by 180° about the origin is (x,y)→(−x,−y) .
What is the image of 1 -6 after a 180 degree counterclockwise rotation about the origin?
A 180° rotation is half a rotation and it doesn't matter if it is clockwise of counter clockwise. When rotating 180° about the origin, the x-coordinate and y-coordinates change sign Thus (1, -6) → (-1, 6) after rotating 180° around the origin.
Why doesn't the direction of rotation clockwise and counterclockwise matter when the angle of rotation is 180?
Because 180 degrees clockwise is the same as 180 degrees counterclockwise.
180 degrees counterclockwise rotation?
Fomula(work with both clockwise/counterclockwise):(-x,-y)
What is the image of (5 4) when it is rotated 180 degrees about the origin?
To find the image of the point (5, 4) when rotated 180 degrees about the origin, you can apply the transformation that changes the signs of both coordinates. Thus, the new coordinates will be (-5, -4). Therefore, the image of the point (5, 4) after a 180-degree rotation about the origin is (-5, -4).
Which is the image of ABC for a 180 and deg counterclockwise rotation about P?
To find the image of ABC for a 180-degree counterclockwise rotation about point P, we would reflect each point of the triangle across the line passing through P. The resulting image of ABC would be a congruent triangle with its vertices in opposite positions relative to the original triangle.
What is the image of point 3 and 5 if the rotation is 180 degrees?
What is the image of point (3, 5) if the rotation is
What is the image of point (4 3) if the rotation is -180?
The answer will depend on where the centre of rotation is. Since that it not specified, the image could by anywhere.
What is the image of point (4 3) if the rotation is -180 degrees?
Conventionally positive angles are measured anticlockwise, by 180° is a half turn regardless of direction. It depends where the centre of rotation is, so where would you like the image to be? If the centre is at, say, (4, 3) then the image will be at (4, 3) regardless of the angle of rotation. If the centre is at, say, (4, 4) then the image will be at (4, 5) If the centre is at, say, the origin, ie (0, 0) then the image will be at (-4, -3).
How do you rotate a figure 180 degrees counterclockwise around the origin?
For every point A = (x,y) in your figure, a 180 degree counterclockwise rotation about the origin will result in a point A' = (x', y') where: x' = x * cos(180) - y * sin(180) y' = x * sin(180) + y * cos(180) Happy-fun time fact: This is equivalent to using a rotation matrix from Linear Algebra! Because a rotation is an isometry, you only have to rotate each vertex of a polygon, and then connect the respective rotated vertices to get the rotated polygon. You can rotate a closed curve as well, but you must figure out a way to rotate the infinite number of points in the curve. We are able to do this with straight lines above due to the property of isometries, which preserves distances between points.
What is the image of point 4 3 if the rotation is -270?
All rotations, other than those of 180 degrees should be further qualified as being clockwise or counter-clockwise. This one is not and I am assuming that the direction of rotation is the same as measurement of polar angles. Also, a rotation is not properly defined unless the centre of rotation is specified. I am assuming that the centre of rotation is the origin. Without these two assumptions any point in the plane can be the image. With the assumptions, for which there is no valid reason, the image is (3, -4).
What is the image of point (3 5) if the rotation is-180?
If the point (3,5) is rotated 180 degrees, it becomes (-3,-5).
