It is: (50-2)*180 = 8640 degrees
48 because (50-2)*180 = sum of interior angles
what is a 50 sided polygon called?
The name of a 50 sided polygon is Pentacontagon.
The name of a 50 sided polygon is Pentacontagon.
360 degrees
It is: (50-2)*180 = 8640 degrees
8640 degrees The sum of the interior angles of an n-sided polygon is: 180(n-2). For n=50, we have 180(50-2)=180(48)=8640 degrees
The sum of the interior angles of a polygon can be found using the formula: (n-2) × 180° Therefore, the interior angles of a pentacontagon; a fifty-sided polygon, will add up to: (50-2) × 180° (48) × 180° 8640°
if you mean the sum of the interior angles, then it is 8640. the formula you use to find the sum of the interior angles of a polygon is (n-2)180, n being the number of sides. in this problem, you would plug in 50 for n, so 50-2=48, and 48x180=8640.
48 because (50-2)*180 = sum of interior angles
Since the 50-sided polygon is a regular polygon, then:The sum of 50 angles = (50 - 2)(180⁰) = 48(180⁰) = 8,640⁰Each angle measure = 8,640⁰/50 = 172.8⁰
what is a 50 sided polygon called?
The name of a 50 sided polygon is Pentacontagon.
The interior angle of a regular polygon with x sides is 180(x-2)/x. As a result, each angle of a regular 50-sided polygon is 172.8. The exterior angles are 7.2
The name of a 50 sided polygon is Pentacontagon.
13agon and 50agon