35,680mm2
Side = 6 mm Area = 216 mm2 Volume = 216 mm3 Area/Volume = 1 per mm
SA = 34.56 mm2
Not clear which area you want. The surface area of the cylinder can only be determined if you give the length of the cylinder as well as its diameter. As you don't give this I conclude you want the area of the ends only. Each end will be the difference between the area of the 100 mm circle and the 30 mm circle. 100 mm diameter area = 7855 sq mm. 30 mm diameter area = 707 sq mm. Therefore area of end = 7148 sq mm, and you have two ends so total = 14296 sq mm
If your ring has an outer radius of 8 mm and an inner one of 5 mm, you will have pi times (routside)2 minus pi times (rinside)2 or about 122.522 square millimeters of area on the top of the ring. Double that if you add in the surface area of the bottom. As to the sides (the inside and outside), we cannot calculate them without a thickness.
Well, honey, a penny has a diameter of about 0.75 inches, so we can calculate the surface area using the formula for the area of a circle. The surface area of a penny is approximately 0.441 square inches. So, there you have it, the glamorous surface area of a humble little penny.
A cylinder if the diameter is 124 mm and the length is 170 mm has a surface area of 90,377.34mm2
To calculate the surface area of an ISMB 200, you need to know its dimensions. The ISMB 200 is an Indian Standard Medium Weight Beam, and its dimensions are: Height: 200 mm Width: 100 mm Flange thickness: 10.2 mm Web thickness: 5.7 mm Length: Typically supplied in standard lengths of 6, 9, 12, or 15 meters To calculate the surface area of an ISMB 200, you need to find the surface area of each of its parts separately and then add them up. The surface area of the flanges and the web can be calculated as follows: Surface area of each flange = Width × Flange thickness × 2 = 100 mm × 10.2 mm × 2 = 2040 mm² Surface area of the web = Height × Web thickness = 200 mm × 5.7 mm = 1140 mm² Total surface area of an ISMB 200 = Surface area of both flanges + Surface area of the web = (2040 mm² + 2040 mm²) + 1140 mm² = 5220 mm² Therefore, the surface area of an ISMB 200 is 5220 square millimeters.
Total surface area = 2*(LW + WH + HL) = 538.76 sq mm.
Assuming that the jewel case is in the shape of a cuboid, the total surface area is 38280 sq mm.
Surface area of the ball = 4*pi*342 = 4624*pi square mm
The surface area of a prism is twice the area of the end plus the area of all the sides. For a prism with a polygon cross-section the area of all the sides if given by the perimeter of the cross-section polygon multiplied by the length of the prism. Assuming you have a prism of cross-section that is a rectangle with sides 4 mm and 3 mm, and is 15 mm long (ie it is an oblong), its surface area is: → surface_area = 2 × (4 mm × 3 mm) + 2 × (4 mm + 3 mm) × 15 mm → surface area = 2 × 12 mm² + 14 mm × 15 mm = 234 mm²
This sphere's surface area is 201.06 mm2
76 square mm
The surface area of a cube with a volume of 512 mm3 is: 384 square mm
The lateral surface area is 549.78mm2
The thickness of a penny is approximately 1.52 mm.