This sphere's surface area is 201.06 mm2
A cylinder if the diameter is 124 mm and the length is 170 mm has a surface area of 90,377.34mm2
The diameter of this sphere is 20 mm
Surface area of the ball = 4*pi*342 = 4624*pi square mm
The lateral surface area is 549.78mm2
In order to answer the question, its height is also required.
A cylinder if the diameter is 124 mm and the length is 170 mm has a surface area of 90,377.34mm2
The diameter of this sphere is 20 mm
Surface area of the ball = 4*pi*342 = 4624*pi square mm
The lateral surface area is 549.78mm2
2700
Not clear which area you want. The surface area of the cylinder can only be determined if you give the length of the cylinder as well as its diameter. As you don't give this I conclude you want the area of the ends only. Each end will be the difference between the area of the 100 mm circle and the 30 mm circle. 100 mm diameter area = 7855 sq mm. 30 mm diameter area = 707 sq mm. Therefore area of end = 7148 sq mm, and you have two ends so total = 14296 sq mm
In order to answer the question, its height is also required.
First find the radius by dividing 23 by 2*pi which works out as 3.660563691 Surface area of the sphere = 4*pi*3.6605636912 = 168.3859298 or about 168 square mm
You didn't finish the question but I assume that you mean the surface area minus the area of the dimples. The surface area of a sphere is 4π*r^2 and since the diameter is 4.1 cm, the radius is half of that or 2.05 cm. Hence the surface area of a sphere of radius 2.05 = 4*π*(2.05)^2 =52.8101725 cm^2 ---------- Now for the dimples. They are circles taken out of the surface of the sphere and hence each has an area of π*r^2 and there are 150 of these. One cm is 10 mm (cm is hundredth, mm is thousandth) So the radius of the dimples is 0.2cm 150 * π * (0.2)^2 = 150 * π * (0.04) = 6πcm^2 = 18.8495556 cm^2 ---------- Now we subtract the area of the dimples from the area of the sphere: 52.8101725 cm^2 18.8495556 cm^2 ------------------------------- Subtract 33.9606165 cm^2 ANSWER: 33.9606165 cm^2 is the surface area of the golf ball minus the area of the dimples.
The area of a circle whose diameter is 6 mm is: 28.27 mm2
surface area = (pai) x (DO 2 - DI 2)/4 = 3.14 (16 x 16 - 10 x 10)/4 = 3.14 x 156 mm = 489.84 square mm
S=pi x dxD S=3.14 x 3 x 40,82 S=384,5244 or rounded 385 mm