-2 & 5
The distance between the points of (2, 3) and (7, 0) is the square root of 34
Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246
Using Pythagoras: 5 squared + 2 squared = √21 which is about 4.58.
the distance between two points is length
Points: (2, 4) and (5, 0) Distance: 5
0 0
7
-2 & 5
Answer: 1
0 is the answer. If you start at -2 2, and end at -2 2, you moved 0 spots so there is no distance.
The distance between the points of (2, 3) and (7, 0) is the square root of 34
Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246
The square root of (2x2)+(5x5) is 5.385164807134504 ' . . . . . . .
Using Pythagoras: 5 squared + 2 squared = √21 which is about 4.58.
The distance between the points of (4, 3) and (0, 3) is 4 units
(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============