The square root of (2x2)+(5x5) is 5.385164807134504
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Points: (2, 4) and (5, 0) Distance: 5
0 0
Answer: 1
Since they are the same point, the distance between them is 0.
Let (x1, y1) = (-2, 0) and (x2, y2) = (5, 3). Distance between two points = square root of [(x2 - x1)2 + (y2 - y1)2] = square root of [(5 - -2)2 + (3 - 0)2] = square root of (72 + 32) = square root of 58
5 is.
The distance between the points of (4, 3) and (0, 3) is 4 units
Points: (2, 4) and (5, 0) Distance: 5
Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246
0 isn't a real number. Distance: the extent or amount of space between two things, points or lines. 0 is not a amount as it is not a number and is the "Distance" were to be 0 then it wouldn't be any leanth away.
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7
The distance between the points of (2, 3) and (7, 0) is the square root of 34
0 0
Answer: 1
Since they are the same point, the distance between them is 0.
Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.