0
The square root of (2x2)+(5x5) is 5.385164807134504
'
.
.
.
.
. . .
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
What is the the distance between the points (2 4) and (5 0)?
Points: (2, 4) and (5, 0) Distance: 5
Find the distance between the points -2 2 and -2 2?
0 0
What is the distance between the points -2 0 and -1 -1?
Answer: 1
Find the distance between the points 4 6 and 4 6?
Since they are the same point, the distance between them is 0.
What is the distance between the points -2 0 and 5 3?
Let (x1, y1) = (-2, 0) and (x2, y2) = (5, 3). Distance between two points = square root of [(x2 - x1)2 + (y2 - y1)2] = square root of [(5 - -2)2 + (3 - 0)2] = square root of (72 + 32) = square root of 58
What is the distance between two points 0 4 and 3 0?
5 is.
Find the distance between the points (4 3) and (0 3).?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the the distance between the points (2 4) and (5 0)?
Points: (2, 4) and (5, 0) Distance: 5
What is the distance between these two points 0 0 and 8 2?
Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246
Why distance cannot be equal to zero?
0 isn't a real number. Distance: the extent or amount of space between two things, points or lines. 0 is not a amount as it is not a number and is the "Distance" were to be 0 then it wouldn't be any leanth away.
What is the distance between the origin and (-3 -4)?
1
What is the distance between points A 2 3 2 and B 0 0 0?
7
What is the distance between points (23) and (70) to the nearest tenth?
The distance between the points of (2, 3) and (7, 0) is the square root of 34
Find the distance between the points -2 2 and -2 2?
0 0
What is the distance between the points -2 0 and -1 -1?
Answer: 1
Find the distance between the points 4 6 and 4 6?
Since they are the same point, the distance between them is 0.
How do you find the distance between the origin of a cartesian coordinate system and a point?
To find the distance between the origin and the point (x,y) use Pythagoras on the right angled triangle which has the points (0, 0), (x, 0), (x, y) - the distance is the hypotenuse of the triangle and so has length: distance = √(x2 + y2) This can be extended to find the distance between any two points (x1, y1) and (x2, y2): distance = √((x2 - x1)2 + (y2 - y1)2) (for the original question (x1, y1) is the origin (0, 0) and the first formula results.)
