5 is.
The distance between the points of (2, 3) and (7, 0) is the square root of 34
To find the distance between the origin and the point (x,y) use Pythagoras on the right angled triangle which has the points (0, 0), (x, 0), (x, y) - the distance is the hypotenuse of the triangle and so has length: distance = √(x2 + y2) This can be extended to find the distance between any two points (x1, y1) and (x2, y2): distance = √((x2 - x1)2 + (y2 - y1)2) (for the original question (x1, y1) is the origin (0, 0) and the first formula results.)
-2 & 5
The distance between two points on a coordinate plane is calculated using the distance formula: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, the coordinates of the two points are (7, 1) and (7, 3). Since the x-coordinates are the same, we only need to calculate the difference in the y-coordinates, which is (3 - 1) = 2. Plugging this into the distance formula gives us: Distance = √((0)^2 + (2)^2) = √4 = 2. Therefore, the distance between the two points is 2 units.
5 is.
The distance between the points of (4, 3) and (0, 3) is 4 units
Points: (2, 4) and (5, 0) Distance: 5
The square root of (2x2)+(5x5) is 5.385164807134504 ' . . . . . . .
0 isn't a real number. Distance: the extent or amount of space between two things, points or lines. 0 is not a amount as it is not a number and is the "Distance" were to be 0 then it wouldn't be any leanth away.
1
7
The distance between the points of (2, 3) and (7, 0) is the square root of 34
0 0
Answer: 1
Since they are the same point, the distance between them is 0.
To find the distance between the origin and the point (x,y) use Pythagoras on the right angled triangle which has the points (0, 0), (x, 0), (x, y) - the distance is the hypotenuse of the triangle and so has length: distance = √(x2 + y2) This can be extended to find the distance between any two points (x1, y1) and (x2, y2): distance = √((x2 - x1)2 + (y2 - y1)2) (for the original question (x1, y1) is the origin (0, 0) and the first formula results.)