The formula is the square root of: (x2-x1)^2 plus (y2-y1)^2
x2+y2+4x+6y-40 = 0 and x = 10+y Substitute the second equation into the first equation: (10+y)2+y2+4(10+y)+6y-40 = 0 2y2+30y+100 = 0 Divide all terms by 2: y2+15y+50 = 0 (y+10)(y+5) = 0 => y = -10 or y = -5 Substitute the above values into the second equation to find the points of intersection: Points of intersection are: (0, -10) and (5, -5)
x2 + y2 = 25radius of 10?x2 + y2 = 100
Points: (x, y) and (x2, y2) Slope = y2-y divided by x2-x
Oh honey, you've got yourself a classic case of finding the average of two points in a coordinate plane. All you need to do is add the x-coordinates (x1 + x2) and divide by 2 to get the x-coordinate of the midpoint. Then do the same for the y-coordinates (y1 + y2), divide by 2, and voila, you've got the y-coordinate of the midpoint. Easy peasy lemon squeezy!
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
y2=-x2-8x+6
X2+y2=25 (x-8)2+y2 =41
There is no expansion for x2 + y2
(y2+13y+22)/(y+2) = (y+11)
4
25x2 - 10xy + y2 = (5x - y)2
(2-r)e-rr
This is not factor-able.
(y - 5)(y - 6)
x2 + y2 = 2r2
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z