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How can you find the length of a line segment in the coordinate plane?
The formula is the square root of: (x2-x1)^2 plus (y2-y1)^2
Where are the points of intersection on the curve and line of x squared plus y squared plus 4x plus 6y minus 40 equals 0 and x equals 10 plus y?
x2+y2+4x+6y-40 = 0 and x = 10+y Substitute the second equation into the first equation: (10+y)2+y2+4(10+y)+6y-40 = 0 2y2+30y+100 = 0 Divide all terms by 2: y2+15y+50 = 0 (y+10)(y+5) = 0 => y = -10 or y = -5 Substitute the above values into the second equation to find the points of intersection: Points of intersection are: (0, -10) and (5, -5)
Which equations correctly represents a circle centered at the origin with a radius of 5?
x2 + y2 = 25radius of 10?x2 + y2 = 100
How do you find the slope when given two points?
Points: (x, y) and (x2, y2) Slope = y2-y divided by x2-x
X1 plus x2 divided by 2 y1 plus y2 divided by 2?
Oh honey, you've got yourself a classic case of finding the average of two points in a coordinate plane. All you need to do is add the x-coordinates (x1 + x2) and divide by 2 to get the x-coordinate of the midpoint. Then do the same for the y-coordinates (y1 + y2), divide by 2, and voila, you've got the y-coordinate of the midpoint. Easy peasy lemon squeezy!
