The edge length of a cube with a diagonal of 9 ft is: 5.196 feet.
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The distance between two tetrahedral voids is 0.866*edge length of the cube.As tetrahedral voids are present at 1/4th of the distance from each corner on a body diagonal of a cube.On each body diagonal there are two tetrahedral voids so making a total of 8 tetrahedral voids in an FCC cube. the distance between two tetrahedral voids is half of the body diagonal of a cube and the body diagonal of a cube is1.732 times of the edge length of the cube
If the length of one edge of a cube is 10cm its volume is: 1,000 cm3
Each edge is 16 cm.
Area = 6s2 where s is the length of an edge.
Edge length will be 8 cm