Lets say the short side (opposite the 30* angle) is X. the long side(opposite the 60* angle) is X times the square root of 3 and the hypotenuse is 2X.
Yes that is an example of how to do the problem but the answer is.
1: Square root 3
2 Square root 3:6
If its a right angle triangle then its side lengths could be 3, 4 and 5
1:square root 3
The sides of a triangle are its lengths are cannot be negative. However, you could place a triangle on coordinate system and some points where the vertices are could be negative numbers.
The list that accompanies the question doesn't contain any numbers that could be the lengths of the sides of a triangle.
There are no numbers on that list that could be the sides of a right triangle. Oh, all right. The following is the answer:
If its a right angle triangle then its side lengths could be 3, 4 and 5
Yes and the given lengths would form an isosceles triangle.
Any number between 3 and 15
If any of its 2 sides is not greater than its third in length then a triangle can't be formed.
1:square root 3
It can't.
The last side length could be between 4 units and 10 units inclusive.
Yes
Yes.
The sides of a triangle are its lengths are cannot be negative. However, you could place a triangle on coordinate system and some points where the vertices are could be negative numbers.
The list that accompanies the question doesn't contain any numbers that could be the lengths of the sides of a triangle.
In a 30-60-90 triangle, the ratio between the lengths of the shorter leg and the hypotenuse is 1:2, and the ratio between the lengths of the longer leg and the hypotenuse is √3:2. Therefore, the possible ratios for the lengths of the two legs are 1:√3, 2:√3, or √3:2. Option C, 1:√3, could be the ratio between the lengths of the two legs of a 30-60-90 triangle.