So that the arcs constructed are at midpoint of the line segment to be bisected.
The problem is that the width of a line is zero. No drawing instrument can manage that!
yes
4 feet
The length is 7 feet and the width is 5 feet
5
no it does not have a width
It is true. A line segment has finite length but no width.
None of them since a thread has a finite length and finite width. A point has neither length nor width whereas a line, line segment and ray do not have any width. A plane has infinite length and width. The nearest approximation is a line segment.
Wrong.
true
= If a rectangle is 10 meters longer than its width what is its width? =
Yes.
Open the compass to a width greater than half the length of AB.Place the compass point at A.Draw arcs above and below the line AB.Move the compass point to B WITHOUT changing the compass setting.Draw arcs above and below AB to intersect them at X and Y.Join XY.XY is the perpendicular bisector of AB.7. Celebrate the successful completion of the task!
false
A line segment has length. That is its only dimension. It does not have any width, or height or depth.
a line or line-segment
1. first draw a line any measurements 2. then get your compass and place it on the left side of your line remembering that the compass has to be more than halfway open then go up to the middle with ur compass and draw one half of a cross with the compass then draw another half a cross below the line not changing the width of the compass but make sure it is in line with the other half cross now take the compass of your page now place the point on the other side of the line and do the same as i just said then you should get two crosses one above the line and one below the finishing touch is get a ruler and where the crosses meet draw a line strainght the way down and then your done i hope that helped i learnt it in a maths lesson