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Q: How do you find projective line if I have to points x1 y1 and x2 y2?
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Calculation of the slope of a straight line?

Find 2 points on the line, (x1,y1 ) (x2, y2) Slope = (y2 - y1)÷(x2-x1) In the equation of a line y = ax + b , a is the slope>


What is the points to form a line?

two points form a line. (x1,y1)(x2,y2)


How do you find the slope of the line that passes through 2 points?

Assume your points are (x1, y1) and (x2, y2). The slope of a line is its rise (the change in y-coordinates) over its run (the change in x-coordinates). So to find the slope of the line, you substitute the correct values into the formula (y2 - y1) / (x2 - x1).


What is the slope of the line that contains the data point?

A slope is a line on a graph that's either positive or negative. The points are where a "y" line and an "x" line meet on the slope line. When you find 2 points, you have to label them x1, y1, then x2, y2. You then need to use the formula y2-y1 over x2-x1.


How do you find the height of a slope given two points?

To find the slope (steepness, not height) of a line when given two points, do the following: Slope = (y2-y1)/(x2-x1), where (x1, y1) is one point, and (x2,y2) is the second point.


How do you find an equation of a line through two points?

Approach by 2 formulas; slope m= (y2-y1)/(x2-x1) and the equation of the line is (y-y1)= m*(x-x1) where point 1 is (x1,y1) and point 2 is (x2,y2)


How can you find an equation line between two pair of points?

Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.


How do you find the gradient of a line from a graph?

Select two points on the graph and suppose their coordinates are (x1, y1) and (x2, y2) then the gradient = (y1 - y2) / (x1 - x2) provided that x1 and x2 are different. If not, the gradient is not defined.


How do you find the distance from two points to the line of an equation?

It is the square root of (x1-x2)^2 + (y1-y2)^2


How do you find The equation of a line given two points needed?

First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1): y - y1 = m(x - x1) Just replace x1 and y1 with the coordinates of the point, and m with with the slope.


Can any 2 points on a straight line be used to find the gradient?

Yes beccause: (y1-y2)/(x1-x2) = gradient


Find the slope of the line that passes through the points A(-2, -1) B(3, 5)?

The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.