answersLogoWhite

0

7

User Avatar

Sonny Borer

Lvl 10
5y ago

What else can I help you with?

Related Questions

What are two integers 7 units from 0?

7 and -7


What two numbers are 7 units from 0 on a number line?

+7 and -7.


How do you factor x2 plus 14x plus 49 equals 0?

ax2 + bx + c = 0 x2 + 14x + 49 = 0 Figure out what two numbers can be multiplied to get the sum of a + c and can be added together to equal b. 7 * 7 = 49 7 + 7 = 14 (x + 7)(x + 7) = 0 Solve each for x: x + 7 = 0 x = -7 x + 7 = 0 x = -7


What is the ISBN of Two for the Dough?

The ISBN of Two for the Dough is 0-684-19638-7.


X squared plus 7X equals zero?

To solve the equation ( x^2 + 7x = 0 ), you can factor it as ( x(x + 7) = 0 ). This gives two solutions: ( x = 0 ) and ( x + 7 = 0 ), which simplifies to ( x = -7 ). Thus, the solutions are ( x = 0 ) and ( x = -7 ).


Two Jar of 7 liter and 13 liter full of water and one jar of 19 liter is empty. Distribute the 20 liter water in two jar of 10 liter each using the three jars only.?

Solution!!!! 0 13 7 7 13 0 7 6 7 14 6 0 14 0 6 1 13 6 1 12 7 8 12 0 8 5 7 15 5 0 19 1 0 12 1 7 12 8 0 5 8 7 5 13 2 18 0 2 18 2 0 11 2 7 11 9 0 4 9 7 4 13 3 17 0 3 17 3 0 10 3 7 10 10 0 ==== Solution with lesser number of steps: 0 13 7 13 0 7 19 0 1 19 1 0 12 1 7 12 8 0 5 8 7 5 13 2 18 0 2 18 2 0 11 2 7 11 9 0 4 9 7 4 13 3 17 0 3 17 3 0 10 3 7 10 10 0


What is X squared minus 7X equals zero?

The equation ( x^2 - 7x = 0 ) can be factored as ( x(x - 7) = 0 ). This gives two solutions: ( x = 0 ) and ( x = 7 ). Therefore, the values of ( x ) that satisfy the equation are 0 and 7.


What numbers multiply to get 30 but add to get 7?

a+b=-7 rearrange: b= -a-7=-(a+7) substitute into: ab=30 -a(a+7)=30 -a^2-7a-30=0 a^2+7a+30=0 x = complex number, therefore there are no two Real numbers that exist that satisfy these two conditions.


What is 0-7?

7


What is 15 times 0 times 13 plus 7?

15*0=0 0*13=0 0+7=7 The answer is 7


What is the answer for 0 divided by 7?

0


How do you solve 5z2-33z-14?

5z2-33z-14 = 0 (5z + 2)(z - 7) = 0 {factored into two binomials} 5z + 2 = 0 or z - 7 = 0 {set each factor equal to 0} 5z = -2 or z = 7 {subtracted 2 and added 7, respectively} z = -2/5 or z = 7 {divided left equation by 5}