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When n is positive, then the opposite of n is negative while the absolute value of n is positive. So the opposite and absolute have different signs.

Q: How does the opposite of n differ from the absolute value of n?

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Zero. The absolute value |n| is positive for any real number. Subtracting it from itself is zero.

The absolute value of -9.3 is 9.3.

n+6

Positive plus positive is positive. Negative plus negative is negative. Positive plus negative is positive if the absolute value of the positive number is greater than the absolute value of the negative one. Positive plus negative is negative if the absolute value of the negative number is greater than the absolute value of the positive one.

n+6

Mean absolute deviation = sum[|x-mean(x)|]/n Where mean(x) = sum(x)/n and n is the number of observations. |y| denotes the absolute value of y.

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Since n is positive, |n| = n, so you have 2n - n = n. The difference is n.

The symbol for the operation of absolute value is |n| but I don't know why a common symbol is needed.....

when -n = x and x is a negative #, n is the absolute value of x

Its distance from zero, always a positive number. The absolute value of a positive number is that number. The absolute value of a negative number is its positive equivalent. Usually denoted by vertical bars |n| The absolute value of both 7 and -7 is 7 |-7| = 7 |7| = 7 * * * * * Minor error above: the absolute value of 0 is 0, so not "always a positive number".

If you use n terms from the Taylor expansion, the absolute value of the error is less than [|x|^(2n+1)]/(2n+1)!If you use n terms from the Taylor expansion, the absolute value of the error is less than [|x|^(2n+1)]/(2n+1)!If you use n terms from the Taylor expansion, the absolute value of the error is less than [|x|^(2n+1)]/(2n+1)!If you use n terms from the Taylor expansion, the absolute value of the error is less than [|x|^(2n+1)]/(2n+1)!