10 is 2 in binary
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Use the Pythagorean theorem. a^2 + b^2 = c^2 a = base b = length c = hypotenuse 8^2 + b^2 = 10^2 b^2 = 10^2 - 8^2 b = sqrt(10^2 - 8^2) b = sqrt(100 - 64) b = sqrt(36 b = 6 ------------------the length
-5a + b = 2 AND -a - 5b = 0 -5a + b = 2 b = 2 + 5a *using above -a - 5b = 0 -a - 5(2 + 5a) = 0 -a - 10 - 25a = 0 -26a = 10 a = 10/-26 *using 'a' value 5a + b = 2 5(10/-26) + b = 2 -25/13 -2 = -b b = 51/13 Therefore a = 10/-26 b = 51/13
(a+b)/2 - 10 a+b divided by 2 and then minus 10
8+b^2=10 b^2=2 Subtracted 8 from both sides b=2^1/2 Took square root of both sides
When dividing a smaller number into a larger number, subtract the exponents. 8 x 10^5 divided by 4 x 10^2 = 2 x 10^3