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What is the length of a right triangle if the base is 8 and hypotenuse is 10?
Use the Pythagorean theorem. a^2 + b^2 = c^2 a = base b = length c = hypotenuse 8^2 + b^2 = 10^2 b^2 = 10^2 - 8^2 b = sqrt(10^2 - 8^2) b = sqrt(100 - 64) b = sqrt(36 b = 6 ------------------the length
How do you solve similtaneously -5a plus b equals 2 and -a -5b equals 0?
-5a + b = 2 AND -a - 5b = 0 -5a + b = 2 b = 2 + 5a *using above -a - 5b = 0 -a - 5(2 + 5a) = 0 -a - 10 - 25a = 0 -26a = 10 a = 10/-26 *using 'a' value 5a + b = 2 5(10/-26) + b = 2 -25/13 -2 = -b b = 51/13 Therefore a = 10/-26 b = 51/13
What is the algebraic expression for the word phrase 10 less than half the sum of a and b?
(a+b)/2 - 10 a+b divided by 2 and then minus 10
8 plus b squared equals 10 what is b?
8+b^2=10 b^2=2 Subtracted 8 from both sides b=2^1/2 Took square root of both sides
How do you divide using scientific notation?
When dividing a smaller number into a larger number, subtract the exponents. 8 x 10^5 divided by 4 x 10^2 = 2 x 10^3
What is the length of a right triangle if the base is 8 and hypotenuse is 10?
Use the Pythagorean theorem. a^2 + b^2 = c^2 a = base b = length c = hypotenuse 8^2 + b^2 = 10^2 b^2 = 10^2 - 8^2 b = sqrt(10^2 - 8^2) b = sqrt(100 - 64) b = sqrt(36 b = 6 ------------------the length
How do you solve similtaneously -5a plus b equals 2 and -a -5b equals 0?
-5a + b = 2 AND -a - 5b = 0 -5a + b = 2 b = 2 + 5a *using above -a - 5b = 0 -a - 5(2 + 5a) = 0 -a - 10 - 25a = 0 -26a = 10 a = 10/-26 *using 'a' value 5a + b = 2 5(10/-26) + b = 2 -25/13 -2 = -b b = 51/13 Therefore a = 10/-26 b = 51/13
What is the algebraic expression for the word phrase 10 less than half the sum of a and b?
(a+b)/2 - 10 a+b divided by 2 and then minus 10
Two numbers have a sum of 40 the difference is 10 what are the two numbers?
2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
8 plus b squared equals 10 what is b?
8+b^2=10 b^2=2 Subtracted 8 from both sides b=2^1/2 Took square root of both sides
What is the base of a triangle when the area is 30 and the height is 10?
The equation for the area of a triangle goes as followed: A = [(b)(h)]/2 A = Area b = base h = height Your known values are A = 30 h = 10 Unknown values b = ? Simply plug in your known values to find your unknown value: 30 = [(b)(10)]/2 (30)(2) = (b)(10) 60 = (b)(10) (60)/(10) = b b = 6
Find angle B in triangle ABC if a is 10 b 16 and c 12?
We can use the law of cosines here. ( remember, side b is opposite angle B) DEGREE MODE! b^2 = a^2 + c^2 - 2ac cos(B) 16^2 = 10^2 + 12^2 - 2(10)(12) cos(B) 256 = 244 - 240(cos B ) 12 = -240(cos B ) -0.05 = cosB arcos(-0.05) = B B = 93 degrees
What is the length of the side AB in the triangle?
You take the Square root of A^2 + b^2 So Side A 10 Inches, b=10 Inches a. 10^2 = 100 b. 10^2 = 100 Total 200 Square root of 200 = 14.142......
How do you divide using scientific notation?
When dividing a smaller number into a larger number, subtract the exponents. 8 x 10^5 divided by 4 x 10^2 = 2 x 10^3
What adds up to -2 and multiplies to -10?
The answer is √11 - 1, and -1 - √11. Here is one method of finding it: Let a + b = -2, and ab = -10. Now, (a + b)2 = a2 + 2ab + b2, and (a - b)2 = a2 - 2ab + b2. Subtracting, we have (a + b)2 - (a - b)2 = 4ab = - 40, whence (a - b)2 = (a + b)2 + 40 = 4 + 40 = 44, and a - b = √44 = 2√11. Adding a + b = -2, and a - b = 2√11, we have, 2a = 2√11 - 2, giving a = √11 - 1, and b = -1 - √11. The sum of these is clearly -2, and their product is -10.
A 10' pole stands 10' to the left of a 100' pole on a level plane At what height on the 100' pole could it be bent over touching the 10' pole and the ground?
44.5' Using Pythagoras' theorem a^2 = b^2 +c^2 and the fact that the pole is 100' in length, we can make two simultaneous equ's: a^2 = b^2 + (10)^2 and a + b = 100 /| a / |b /___ | 10
10 liter bucket and 3 liter bucket how do get 5 liters exactly?
10 L - A 3 L -B 1) B --> A fill B 2) B --> A fill B 3) B --> A A will have 9 L again fill B 4) B --> A A will have 10 and B will have 2 empty A 5) B --> A B will have 0 and A will have 2 fill B 6) B --> A A will have 5L problem solved in 6 steps
