Divide both sides by 6: 3 - r = 0, so r = 3 satisfies the equation.
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r=0 is the solution...
a could equal 0 and r could equal 27a could equal 1 and r could equal 23a could equal 2 and r could equal 19a could equal 3 and r could equal 15a could equal 4 and r could equal 11a could equal 5 and r could equal 7a could equal 6 and r could equal 3a could equal 7 and r could equal - 1It could be any of these and many, many more...is it the whole question?
r = 4
if you have 12r and you minus 4r it doesn't equal 48. it would equal 8r to find out what r is i would have to see the whole problem
0, within statistical error.