20(x + 3) - (x + 2)(x - 3)
After distributing 20 and multiplying (x + 2) and (x - 3) together:
20x + 60 - (x^2 - 3x + 2x - 6)
After combining like terms:
20x + 60 - (x^2 - x - 6)
After distributing the negative sign to the quantity (x^2 - x - 6):
20x + 60 - x^2 + x + 6
After combining like terms:
- x^2 + 21x + 66
Answer:
20(x + 3) - (x + 2)(x - 3) = - x^2 + 21x + 66
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This formula can be better expressed as [(1+2)(2+3)(3+4)] = (20+x)/2. Simplifying, we get 2[(3)(5)(12)] = 20+x. Then the equation becomes 2[180] = 20+x, or 360 = 20+x. Transferring 20 to the other side, we get 360-20 = x. So, x = 340.
(20 * x) + 3 = 5 20 * x = 2 x = 1/10
If you mean: x^2 +12x +20 then it is (x+2)(x+10) when factored
x + x + 1 + x + 2 + x + 3 = -144x + 6 = 144x = 8x = 2
3x^2+3x-60=3(x^2+x+20)=3(x+5)(x-4)
This formula can be better expressed as [(1+2)(2+3)(3+4)] = (20+x)/2. Simplifying, we get 2[(3)(5)(12)] = 20+x. Then the equation becomes 2[180] = 20+x, or 360 = 20+x. Transferring 20 to the other side, we get 360-20 = x. So, x = 340.
(20 * x) + 3 = 5 20 * x = 2 x = 1/10
20
You don't know that?! If x=3, then 6x is 6x3. So 18 plus 2 is.....20!!
2x/3=x/2+20 (2x/3=x/2+20)6 4x=3x+120 4x-3x=120 x=120
x+3 = 20 x = 20-3 x = 17
3x + 2 = x - 18 - 2 = - 2 3x = x - 20 - x = - x 2x = -20 /2 = /2 x = -10
20/(5 x 2) + 3 = 5 20/10 + 3 = 5 2 + 3 = 5
20 x 3 and 20 + 2
If you mean: x^2 +12x +20 then it is (x+2)(x+10) when factored
3x^2=-20 so x^2=-20/3 this has no real roots but the plus of minus i(square root of 20/3) is a solution if we allow complex numbers.
x + x + 1 + x + 2 + x + 3 = -144x + 6 = 144x = 8x = 2