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Which number is between point S and point T on the number line?
k*S + (1-k)*T where k is any number between 0 and 1.
Alpha sequence r k r j s k s j t?
I thinks that might be r k r j s k s j t k Repeats the sequence of the letter rr ss tt. . . . and k...j ... k ... j ... k ... j ... k ---> line 1 r......r.....s....s.....t.... ---> line 2 Match line 1 with line 2. I hope it is clear and correct.
What is 4t2 minus 16 over 8 divided by t minus 2 over 6 simplified?
(4t2 - 16)/8 ÷ (t - 2)/6 = [4(t2 - 4)/8] x 6/(t - 2) = (t2 - 22)/2 x 6/(t - 2) = (6/2)[(t + 2)(t - 2)/(t - 2)] = 3(t + 2) = 3t + 6
What is brackets t plus 2 to the power of 2?
x2 is the same as x times x. In this case x = t+2 so we can say (t+2)2 is (t+2)(t+2) or t2+4t+4
What is Make x the subject of the formulae T equals 4x plus 8?
T = 4x + 8 Subtract 8 from both sides: T - 8 = 4x Divide both sides by 4: T/4 - 2 = x or x = T/4 - 2
What are the release dates for The Bigelow Theatre - 1950 T-K-O- 2-4?
The Bigelow Theatre - 1950 T-K-O- 2-4 was released on: USA: 29 October 1951
When f varies jointly as a and t and inversely as the square of b what is the answer when determining f when k equals 3 a equals 4 t equals 6 and b equals 2?
I am assuming that k is the constant of proportionality so that f = k*a*t/b2 = 3*4*6/22 = 18
How many phonemes in catch?
There are 4 phonemes in the word "catch": /k/ /æ/ /t/ /ʃ/.
What is composite transformation?
I assume that "Th,3" is translation by "h" in the x direction and "3" in the y direction- that is, that Th,3(x, y)= (x+h, y+3)- and that "T-2, k" is translation by "-2" in the x direction and "k" in the y direction- that is, that T-2,k(x,y)= (x-2, y+ k). If that is so then Th,3 x T-2,k(-3, 0)= Th,3(-3-2, 0+k)= Th,3(-5,k)= (-5+h, 3+k)= (-4,8). That is, -5+h= -4 and 3+ k= 8. Now, what are h and k? Once you know that, finding Th,3x T-2,k(2, -1) should be easy.
Which number is between point S and point T on the number line?
k*S + (1-k)*T where k is any number between 0 and 1.
What has the author T K So written?
T. K. So has written: 'Chinese chess, 2'
How many phonemes are in the word turkey?
There are 3 phonemes in the word "turkey": /t/, /er/, /k/.
What is T plus 2over 3plus T-4over6?
(t + 2)/3 + (t - 4)/6 (the common denominator 6) = [(t + 2)(2)]/(3)(2) + (t - 4)/6 = (2t + 4)/6 + (t - 4)/6 = (2t + 4 + t - 4)/6 = 3t/6 = t/2
What is an expression for t divided by 2 - 4?
-2
How many syllables does tooth have?
Normally 31. 2 for each T = 4 4 for each O = 8 3 for the H, C, and K = 9 4 for the P = 4 1 for the I = 1 5 for the S = 5
What are the release dates for Martin - 1992 Love T-K-O- 4-5?
Martin - 1992 Love T-K-O- 4-5 was released on: USA: 7 October 1995
Code of K'maps i n C plus plus?
#include<iostream> #include<string.h> //#include<graphics.h> //#include<dos.h> #include<math.h> using namespace std; int main() { // clrscr(); int c=1,c1=4,c2=1,c3=1,r[2000][10],c4=1,c5=1,p[2000][10],q[2000][10],o[2000][10],t[2000][10],s[2000][10],w[2000][10],i,l=1,j,k,m,u[2000][10],a[2000][10],v,e=0,g=1,f=1,h=0,b[2000][10],z[2000][10],y[6000][5],x[2000][10]; cout<<"Enter 0 for not selecting and 1 for selecting\n"; for(i=0;i<=15;i++) { cout<<"Enter the value for "<<i<<":"; cin>>v; if(v==1) { a[c][5]=i; m=i; while(c1!=0) { a[c][c1]=m%2; m=m/2; c1--; } c++; c1=4; } } for(i=1;i<c;i++) { for(j=1;j<c;j++) { for(k=1;k<=4;k++) { if(a[i][k]+a[j][k]==1) e++; } if(e==1) { for(k=1;k<=4;k++) { if(a[i][k]+a[j][k]!=1) b[f][g]=a[i][k]; else b[f][g]=3; g++; } b[f][5]=a[i][5]; b[f][6]=a[j][5]; g=1; f++; h++; } e=0; } if(h==0) { for(k=1;k<=4;k++) x[c2][k]=a[i][k]; c2++; } h=0; } c=0; for(i=1;i<f;i++) { for(j=1;j<i;j++) { for(k=1;k<=4;k++) { if(b[i][k]==b[j][k]) c++; } if(c!=4) e++; c=0; } if(e==i-1) { for(k=1;k<=6;k++) u[h+1][k]=b[i][k]; h++; } e=0; } for(i=1;i<=h;i++) { if(u[i][7]!=4) { for(j=1;j<=h;j++) { if(u[j][7]!=4) { if((u[i][6]==u[j][5])(u[i][6]==u[j][5])(u[i][5]==u[j][5])(u[i][5]==u[j][6])) { for(k=1;k<=h;k++) { if(u[j][6]==u[k][5]u[j][6]==u[k][6]u[j][5]==u[k][5]u[j][5]==u[k][6]) { for(e=1;e<=h;e++) { if(i!=j&&i!=k&&i!=e&&j!=k&&j!=e&&k!=e) { if(u[k][6]!=u[e][5]&&u[k][6]!=u[e][6]&&u[k][6]!=u[e][6]&&u[k][6]!=u[e][5]) u[j][7]=4; } } } } } } } } } cout<<endl; f=h+1; e=0;h=0;g=1;l=1;c=1; for(i=1;i<f;i++) { for(j=1;j<f;j++) { for(k=1;k<=4;k++) { if(u[i][k]+u[j][k]==1) e++; if((u[i][k]+u[j][k]==3)(u[i][k]+u[j][k]==4)) e=2; } if(e==1) { for(k=1;k<=4;k++) { if(u[i][k]+u[j][k]!=1&&u[i][k]+u[j][k]!=6) z[l][g]=u[i][k]; else z[l][g]=3; g++; } g=1; l++; h++; } e=0; } if(h==0) { for(k=1;k<=7;k++) w[c3][k]=u[i][k]; c3++; } h=0; } c=0; for(i=1;i<l;i++) { for(j=1;j<i;j++) { for(k=1;k<=4;k++) { if(z[i][k]==z[j][k]) c++; } if(c!=4) e++; c=0; } if(e==i-1) { for(k=1;k<=4;k++) t[h+1][k]=z[i][k]; h++; } e=0; } l=h+1; e=0;h=0;g=1;m=1;c=1;c1=4; for(i=1;i<l;i++) { for(j=i+1;j<l;j++) { for(k=1;k<=4;k++) { if(t[i][k]+t[j][k]==1) e++; if(t[i][k]+t[j][k]==3t[i][k]+t[j][k]==4) e=2; } if(e==1) { for(k=1;k<=4;k++) { if(t[i][k]+t[j][k]!=1&&t[i][k]+t[j][k]!=6) y[m][g]=t[i][k]; else y[m][g]=3; g++; } g=1; m++; h++; } e=0; } if(h==0) { for(k=1;k<=4;k++) r[c4][k]=t[i][k]; c4++; } h=0; } c=0;h=0; for(i=1;i<m;i++) { for(j=1;j<i;j++) { for(k=1;k<=4;k++) { if(y[i][k]==y[j][k]) c++; } if(c!=4) e++; c=0; } if(e==i-1) { for(k=1;k<=4;k++) s[h+1][k]=y[i][k]; h++; } e=0; } f=h+1; e=0;h=0;g=1;l=1;c=1; for(i=1;i<f;i++) { for(j=1;j<f;j++) { for(k=1;k<=4;k++) { if(s[i][k]+s[j][k]==1) e++; if((s[i][k]+s[j][k]==3)(s[i][k]+s[j][k]==4)) e=2; } if(e==1) { for(k=1;k<=4;k++) { if(s[i][k]+s[j][k]!=1&&s[i][k]+s[j][k]!=6) q[l][g]=s[i][k]; else q[l][g]=3; g++; } g=1; l++; h++; } e=0; } if(h==0) { for(k=1;k<=4;k++) p[c5][k]=s[i][k]; c5++; } h=0; } c=0; for(i=1;i<l;i++) { for(j=1;j<i;j++) { for(k=1;k<=4;k++) { if(q[i][k]==q[j][k]) c++; } if(c!=4) e++; c=0; } if(e==i-1) { for(k=1;k<=4;k++) o[h+1][k]=q[i][k]; h++; } e=0; } for(i=1;i<=h;i++) { cout<<1; } cout<<endl; for(i=1;i<c2;i++) { if(x[i][1]==0) cout<<"A'"; if(x[i][1]==1) cout<<"A"; if(x[i][2]==0) cout<<"B'"; if(x[i][2]==1) cout<<"B"; if(x[i][3]==0) cout<<"C'"; if(x[i][3]==1) cout<<"C"; if(x[i][4]==0) cout<<"D'"; if(x[i][4]==1) cout<<"D"; cout<<"+"; } c=0; for(i=1;i<c3;i++) { if(w[i][7]!=4) { if(w[i][1]==0) cout<<"A'"; if(w[i][1]==1) cout<<"A"; if(w[i][2]==0) cout<<"B'"; if(w[i][2]==1) cout<<"B"; if(w[i][3]==0) cout<<"C'"; if(w[i][3]==1) cout<<"C"; if(w[i][4]==0) cout<<"D'"; if(w[i][4]==1) cout<<"D"; cout<<"+"; } } cout<<endl; c=0; for(i=1;i<c4;i++) { for(j=1;j<=h;j++) { if(((o[j][1]-r[i][1])==2(o[j][1]-r[i][1])==3(o[j][1]-r[i][1])==0)&&((o[j][2]-r[i][2])==2(o[j][2]-r[i][2])==3(o[j][2]-r[i][2])==0)&&((o[j][3]-r[i][3])==2(o[j][3]-r[i][3])==0(o[j][3]-r[i][3])==3)&&((o[j][4]-r[i][4])==2(o[j][4]-r[i][4])==0(o[j][4]-r[i][4])==3)) c++; } for(j=1;j<c5;j++) { if(((p[j][1]-r[i][1])==2(p[j][1]-r[i][1])==3(p[j][1]-r[i][1])==0)&&((p[j][2]-r[i][2])==2(p[j][2]-r[i][2])==3(p[j][2]-r[i][2])==0)&&((p[j][3]-r[i][3])==2(p[j][3]-r[i][3])==0(p[j][3]-r[i][3])==3)&&((p[j][4]-r[i][4])==2(p[j][4]-r[i][4])==0(p[j][4]-r[i][4])==3)) c++; } if(c==0) { if(r[i][1]==0) cout<<"A'"; if(r[i][1]==1) cout<<"A"; if(r[i][2]==0) cout<<"B'"; if(r[i][2]==1) cout<<"B"; if(r[i][3]==0) cout<<"C'"; if(r[i][3]==1) cout<<"C"; if(r[i][4]==0) cout<<"D'"; if(r[i][4]==1) cout<<"D"; cout<<"+"; } c=0; } cout<<endl; for(i=1;i<c5;i++) { if(p[i][1]==0) cout<<"A'"; if(p[i][1]==1) cout<<"A"; if(p[i][2]==0) cout<<"B'"; if(p[i][2]==1) cout<<"B"; if(p[i][3]==0) cout<<"C'"; if(p[i][3]==1) cout<<"C"; if(p[i][4]==0) cout<<"D'"; if(p[i][4]==1) cout<<"D"; cout<<"+"; } // getch (); }
