It is not possible to solve the equation 2k3-4t k 2 t 4 because it is not clear.
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k*S + (1-k)*T where k is any number between 0 and 1.
I thinks that might be r k r j s k s j t k Repeats the sequence of the letter rr ss tt. . . . and k...j ... k ... j ... k ... j ... k ---> line 1 r......r.....s....s.....t.... ---> line 2 Match line 1 with line 2. I hope it is clear and correct.
(4t2 - 16)/8 ÷ (t - 2)/6 = [4(t2 - 4)/8] x 6/(t - 2) = (t2 - 22)/2 x 6/(t - 2) = (6/2)[(t + 2)(t - 2)/(t - 2)] = 3(t + 2) = 3t + 6
x2 is the same as x times x. In this case x = t+2 so we can say (t+2)2 is (t+2)(t+2) or t2+4t+4
T = 4x + 8 Subtract 8 from both sides: T - 8 = 4x Divide both sides by 4: T/4 - 2 = x or x = T/4 - 2