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(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)

(multiply x + 1 by x2, and subtract the product from the dividend)

1. x2(x + 1) = x3 + x2

2. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7

(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)

1. 2x(x + 1) = 2x2 + 2x

2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7

(multiply x + 1 by -4, and subtract the product from -4x + 7)

1. -4(x + 1) = -4x - 4

2. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)

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Q: When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
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