I assume you mean. 4X - 3Y = -36 subtract 4X from each side -3Y = -4X -36 divide both sides by -3 Y = 4/3X + 12 12 is Y intercept
-4x + 3y = 9
3y = 4x + 9 -4x + 3y = 9 is the standard form
x = 3 and y = 0
4x + 3y = 6y 4x = 3y 4/3 x = y The slope is 4/3 and the y intercept is 0.
I assume you mean. 4X - 3Y = -36 subtract 4X from each side -3Y = -4X -36 divide both sides by -3 Y = 4/3X + 12 12 is Y intercept
5x+3y
-4x + 3y = 9
3y = 4x + 9 -4x + 3y = 9 is the standard form
3y=4x+9.....-4xAnswer: 4x-3y=9
4x + 3y=9 x=0 y=3
4x+3y = 12 3y = -4x+12 y = -4/3x+4
4x + 3y = 8x + y so 3y - y = 8x - 4x ie 2y = 4x so y = 2x
4x+3y = 6 3y = -4x+6 y = -4/3x+2 in slope intercept form
x = 3 and y = 0
4x + 3y = 6y 4x = 3y 4/3 x = y The slope is 4/3 and the y intercept is 0.
6x plus 3y minus 2x plus 5y equals 4x plus 8y.