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Q: Is 5xy plus 2x plus 1 equals 0 a quadratic equation?

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9

5xy+4=9 is the problem, right? 5xy+4=9. Now subtract the 4 from both sides. 5xy=5. Ok, then, that looks less scary. Now, divide both sides by 5, to get xy=1. Hmm, a lot simpler. Now, divide both sides by x to get y by itself. So, y=1/x. Alright. That's your line! No, its not a straight line. There is a vertical asymptote where x=0, and the two segments aren't straight. But that's a simpler form of the equation. Hope that helped!

All six of them

It is: 7a/5xy

4x^2+2xy-3y^2-2x^2+5xy-2y2Collect the like terms=2x^2+7xy-5y^2We cannot factorise it because the end term is a negative whilst the second-last term is positive.

Related questions

5xy+4=9

9

x2 + 5xy - 18y2 can not be factored.

What is : 5xy- x2t + 2xy + 3x2t

5xy+4=9 is the problem, right? 5xy+4=9. Now subtract the 4 from both sides. 5xy=5. Ok, then, that looks less scary. Now, divide both sides by 5, to get xy=1. Hmm, a lot simpler. Now, divide both sides by x to get y by itself. So, y=1/x. Alright. That's your line! No, its not a straight line. There is a vertical asymptote where x=0, and the two segments aren't straight. But that's a simpler form of the equation. Hope that helped!

1xy

1xy

It is 5xy + 5x.

The GCF is 5xy.

All six of them

In the given expression you replace x by 2 and y by 1. Thus 5xy + 7x2 - 12y = 5*x*y + 7*x2 - 12*y = 5*2*1 + 7*22 - 12*1 = 10 + 28 - 12 = 26

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared". In this question there is no symbol before 5xy.