Chat with our AI personalities
Proof: P{T>n+m/T>n}=P{T>n+m,T>n}/P{T>n} (Bayes theorem) =P{T>n+m}/P{T>n} =((1-p)^(n+m))/(1-p)^n = (1-p)^(n+m-n) = (1-p)^m (1-p)^m = {T>m} So T>m has the same probability as T>m+n given that T>n, which means it doesn't care (or don't remember) that n phases had passed.
p v = n r t v = n r t / p
please excuse my dear aunt sally a x u i d u r p l v d b e o t i i t n n i s t r t e p i i a h n l o o c e t i n n t s s c i e a o s t n i o n
If you know the time, t, taken for N (complete) oscillations then the period, P, is P = t/N
to hard forget it