First white = 10/20
second white = 9/19
third white = 8/18
fourth white = 7/17
firth white = 6/16
Total probability = 10/20 x 9/19 x 8/18 x 7/17 x 6/16
= 21/1292
~= 0.0163
It is (1/2)5 = 1/32
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.
The probability is 0.3692
There is a probability of 3 that it will be blue.
It is (1/2)5 = 1/32
Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.
A bag of marbles contains 13 marbles. 5 Blue, 3 Yellow, 4 Green and 1 Red. Leave all answers as a ratio in lowest terms. 18 points On a single draw, what is the probability of drawing a yellow marble? What is the probability of not drawing a yellow marble? What are the odds in favor of drawing a blue marble? What is the probability of drawing a red or yellow marble? What is the probability of drawing a purple marble? If you had to bet on drawing a marble of a certain color what color would you not choose?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
5/15 = 1/3 = 33 and 1/3 percent
There are a total of 25 Marbles The chances are 3 out of 25 drawing a Red marble. 3/25 = 12% chance of drawing a red marble
To calculate the probability of not drawing two green marbles, we first find the probability of drawing a green marble on the first draw, which is 5/20 since there are 5 green marbles out of a total of 20 marbles. The probability of not drawing a green marble on the first draw is 1 - 5/20 = 15/20. Since the marbles are replaced, the probability of not drawing a green marble on the second draw is also 15/20. Therefore, the probability of not drawing two green marbles is (15/20) * (15/20) = 225/400 = 9/16 or 56.25%.
The theoretical probability of randomly drawing a green marble can be calculated by dividing the number of green marbles by the total number of marbles in the bag. In this case, there are 12 green marbles out of a total of 5 red marbles + 8 blue marbles + 12 green marbles, which is 25 marbles in total. Therefore, the theoretical probability of drawing a green marble is 12/25 or 48%.
The answer is dependent on whether of not you replace the marbles in the jar. If you do, the probability of drawing a red marble is 9 in 15 or 60%, every time. If you do not replace the marbles, the probability of drawing a red marble is 2 in 8 or 25%.
The probability is 0.3692
There are 13 marbles in total. The order is specified.P(1st is white and the 2ndis purple) = (7/13)(6/12) = (7/13)(1/2) = 7/26.
It depends on how many marbles of each colour you have....