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A ball is thrown straight up with an initial speed of 50 ms how high does it go?
Wiki User
∙ 14y ago
Acceleration of gravity is 9.8 m/s
Ball continues to rise for (50/9.8) seconds. Then its speed is zero before it starts to fall.
During the ascent, average speed is 1/2 (50 + 0) = 25 m/s.
Distance straight up = (average speed) x (time of ascent) = 25 x (50/9.8) = 127.55 meters (rounded).
This is one heck of a toss ! Almost 420 feet up ... like the height of a 40-story building ... before it starts to fall.
But 50 meters per second is a launch at 109 mph ( ! ), so I guess I'll stand by my math. Note that as always, air resistance has been ignored.
Wiki User
∙ 14y ago
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