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A cabin cruiser travels 20 miles in the same time that a power boat travels 40 miles The cruiser travels 5 mph slower than the power boat Find the speed of each boat?
Wiki User
∙ 13y ago
Call the speed in miles per hour of the cabin cruiser c and of the power boat p. From the problem statement, p = c + 5. From the problem statement and the physical law that distance equals the product of speed and time, called t, 20 = ct and 40 = pt. Multiplying the first of these two latter equations by 2 yields 40 = 2ct, and from the lattermost equation, 2ct = pt, since both are equal to 40. Dividing this last equation by t (which can not be zero since covering any finite distance requires a nonzero time) yields 2c = p, and from the first equation given, 2c = c + 5, or c = 5, p = 10, both in miles per hour.
Wiki User
∙ 13y ago
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A hunter leaves his cabin in the morning and travels two miles due south at which point he spots a bear The bear chases him three miles east before the hunter changes direction and runs one mile sout?
The usual trick to this puzzle is that the cabin is at the North Pole.
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Yes, any speed less than 48 mph would be "slower." My car can go faster than both! Seriously, this is not a question. How far are they going? Are the travelling in the same direction? Do they start at the same time? Can they afford the gas at >$4.00/gallon?
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If the bicycle travels 4 miles for the car's 30 miles, then if you divide both numbers by 3 you'll see that the bicycle travels 1 and 1/3rd miles for each 10 miles that the car travels. So, if the car travels a further 10 miles (and has now gone 40 miles) the bicycle will travel a further 1 and 1/3rd miles and its total travelled would be 5 and 1/3rd miles.
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