Initial speed = 60 m/s
Final speed = 80 m/s
Average speed = 70 m/s
Distance = (average speed) x (time) = (70 m/s) x (12 s) = 840 meters
((60m/s+80m/s)/2)x12s=840m
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
Speed = (distance traveled) divided by (time to cover the distance) Speed = (50 meters) / (2 seconds) Speed = 50 meters per 2 seconds Speed = 25 meters per second
2 meters every second. bit pointless
At the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.
((60m/s+80m/s)/2)x12s=840m
an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
3000 N
The rate that you cover a distance is your speed. Speed is a measure of the distance traveled per unit time. If your units are meters and seconds, then your speed would be in meters/second. To find the speed of something you divide the distance it traveled by the time it took to travel that distance. For example if something traveled 40 meters in 10 seconds its speed would be (40 meters)/(10 seconds) = 4 meters/second
Speed = (distance traveled) divided by (time to cover the distance) Speed = (50 meters) / (2 seconds) Speed = 50 meters per 2 seconds Speed = 25 meters per second
2 meters every second. bit pointless
Apply to the equation V=U+at . The answer is 40.
1,531.2 feet in 12 seconds @87 mph
A general formula for distance traveled under constant acceleration is: S = v0t + at2/2 We have to solve system of equations: 50[ft] = 2v0 + 2a, 100[ft] = 4v0 + 8a, Let's add first equation into second -2 times: 0[ft] = 4a, meaning that accleration a is indeed constant and equals 0. In turn, v0 = 25[ft/s], and S = 100[ft] + 3v0 = 175 ft. Body will be at distance of 175 feet after next three seconds.
Speed= Distance / time => Distance = Speed x Time =16x8 = 128m
At the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.
87 miles per hour = 1,531.2 feet per 12 seconds