Q: A plane is uniformly accelerated from 60 ms to 80 m s in 12 seconds what is the distance traveled by the plane during this period?

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((60m/s+80m/s)/2)x12s=840m

an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.

Speed = (distance traveled) divided by (time to cover the distance) Speed = (50 meters) / (2 seconds) Speed = 50 meters per 2 seconds Speed = 25 meters per second

2 meters every second. bit pointless

At the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.

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((60m/s+80m/s)/2)x12s=840m

The formula for distance traveled with uniformly accelerated motion is d = 0.5 * a * t^2, where d is the distance, a is the acceleration, and t is the time. Plugging in the values: d = 0.5 * 40 * 8^2 = 0.5 * 40 * 64 = 1280 meters. Therefore, the car will travel 1280 meters in 8 seconds.

an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.

To find the distance traveled in the first 5 seconds, we multiply the average velocity by the time traveled. If the object's velocity is constant, this distance is equal to the velocity multiplied by the time.

3000 N

Speed = (distance traveled) divided by (time to cover the distance) Speed = (50 meters) / (2 seconds) Speed = 50 meters per 2 seconds Speed = 25 meters per second

2 meters every second. bit pointless

The rate at which you cover a certain distance is known as your speed. It is typically measured in units such as miles per hour (mph) or kilometers per hour (kph). Your speed is calculated by dividing the distance traveled by the time taken to cover that distance.

After 12 seconds, a car traveling at 87 miles per hour would have traveled approximately 1,520 feet. This can be calculated by first converting 87 miles per hour to feet per second, which is about 128 feet per second. Multiplying this by the number of seconds gives the distance traveled.

A general formula for distance traveled under constant acceleration is: S = v0t + at2/2 We have to solve system of equations: 50[ft] = 2v0 + 2a, 100[ft] = 4v0 + 8a, Let's add first equation into second -2 times: 0[ft] = 4a, meaning that accleration a is indeed constant and equals 0. In turn, v0 = 25[ft/s], and S = 100[ft] + 3v0 = 175 ft. Body will be at distance of 175 feet after next three seconds.

Speed= Distance / time => Distance = Speed x Time =16x8 = 128m

At the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.