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Initial speed = 60 m/s

Final speed = 80 m/s

Average speed = 70 m/s

Distance = (average speed) x (time) = (70 m/s) x (12 s) = 840 meters

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Q: A plane is uniformly accelerated from 60 ms to 80 m s in 12 seconds what is the distance traveled by the plane during this period?
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A plane is uniformly accelerated from 60 ms to 80 ms in 12 seconds what is the distance traveled by the plane during this period?

((60m/s+80m/s)/2)x12s=840m


A race car starts from rest and accelerates uniformly of 40ms in 8 seconds. How far will the car travel during the 8 seconds?

The formula for distance traveled with uniformly accelerated motion is d = 0.5 * a * t^2, where d is the distance, a is the acceleration, and t is the time. Plugging in the values: d = 0.5 * 40 * 8^2 = 0.5 * 40 * 64 = 1280 meters. Therefore, the car will travel 1280 meters in 8 seconds.


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an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.


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To find the distance traveled in the first 5 seconds, we multiply the average velocity by the time traveled. If the object's velocity is constant, this distance is equal to the velocity multiplied by the time.


A car whose mass is 2000 kg is accelerated uniformly from rest to speed at 15ms in 10 seconds The net force accelerating the car is?

3000 N


How do you Determine the speed of an object that traveled 50 meters in 2 seconds?

Speed = (distance traveled) divided by (time to cover the distance) Speed = (50 meters) / (2 seconds) Speed = 50 meters per 2 seconds Speed = 25 meters per second


If you traveled 50 meters in 25 seconds what is your distance traveled and average speed?

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What is the rate at which you cover a certain distance?

The rate at which you cover a certain distance is known as your speed. It is typically measured in units such as miles per hour (mph) or kilometers per hour (kph). Your speed is calculated by dividing the distance traveled by the time taken to cover that distance.


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A body is at 50 feet distance in the 2nd second and at 100 feet in the 4th second of its motion. If the motion is uniformly accelerated where will it be after next 3 seconds?

A general formula for distance traveled under constant acceleration is: S = v0t + at2/2 We have to solve system of equations: 50[ft] = 2v0 + 2a, 100[ft] = 4v0 + 8a, Let's add first equation into second -2 times: 0[ft] = 4a, meaning that accleration a is indeed constant and equals 0. In turn, v0 = 25[ft/s], and S = 100[ft] + 3v0 = 175 ft. Body will be at distance of 175 feet after next three seconds.


An automobile traveling at a velocity of 16 meters per second is brought to a full stop in 8 seconds The distance traveled in the 8 seconds is?

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A car accelerates uniformly in a straight line from rest at the rate of 2.2 ms2 What is the speed of the car after it has traveled 62 m Answer in units of ms?

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