Q: A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the?

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A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?

6 inches

Area of the rectangle = (Length x Width) = (12 x 8) = 96Area of the triangle = 1/2 (Base x Altitude) = 1/2 (32 x Alt) = also 96 1/2 (32 x Alt) = 96 32 x Alt = 192 Alt = 192/32 = 6 inches

You either need to find the area of the triangle and subtract it from that of the rectangle OR you find the areas of the bits of the rectangle that are outside the triangle and add them together. Without more details of the triangle, it is not possible to give a more detailed answer.

the area of a triangle is half that of a rectangle made using two of those triangles.

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A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?

A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"

6

6

6

6 inches

The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.

Area of rectangle = l x w: 12 x 8 = 96 sq in Area of triangle is bh/2: 96 = 32(h)/2 192 = 32(h) 6 = h The heigth of the triangle is 6 inches

Area Rectangle = 12 * 8 = 96 sq. in.Area Triangle = 1/2 base * height -> 96 = 16 * height -> 96 / 16 = height = 6 in.

Area of the rectangle = (Length x Width) = (12 x 8) = 96Area of the triangle = 1/2 (Base x Altitude) = 1/2 (32 x Alt) = also 96 1/2 (32 x Alt) = 96 32 x Alt = 192 Alt = 192/32 = 6 inches

The altitude will be 6 inches in length. The area of the rectangle is length (l) times width (w) or l x w = 12 x 8 = 96 The area of a triangle is 1/2 the base (b) times the height (h), or altitude, and, because the area of the triangle is equal to the area of the rectangle, both will have an area of 96. For the triangle, 1/2 b x h = 1/2 x 32 x h = 96, and 16 x h = 96, and h = 6

You either need to find the area of the triangle and subtract it from that of the rectangle OR you find the areas of the bits of the rectangle that are outside the triangle and add them together. Without more details of the triangle, it is not possible to give a more detailed answer.