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A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altitu?
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A rectangle and a triangle have equal areas?
it is possible, if the triangle is bigger than the rectangle, for example the rectangle has a base of 5 and height of 2-- so the area is 10; and then the triangle has a base of 5 and a height of 4-- the area is also 10.
What is the rectangle method in math?
The term "rectangle method" is used in different ways in math, but I will guess that your question is related to finding areas on a Geoboard. A Geoboard has a grid of pegs; you can make outlines of figures by stretching elastic bands around the pegs. If your figure is a triangle, you can find it's area by making the smallest rectangle which will enclose the triangle (The rectangle should have vertical and horizontal sides). The area of the rectangle can be found easily by multiplying the length by the width. The area of the triangle is half of the area of the rectangle.
The perimeter of a rectangle is 22 inches and the inch measure of each side is a natural number how many different areas in square inches can the rectandgl have why?
Suppose the rectangle has length L and width W where, as per convention, L >= W. Now Perimeter = 22 = 2(L+W) so L+W = 11 L is a whole number >=11/2 ie L >= 6 Also, W>0 so L <= 10. Thus L = 6,7,8,9,10 giving 5 possible areas for the rectangle.
How do you calculate the area of one arrow sign?
To find the area of an arrow you can first divide it into two shapes, a rectangle and triangle. First find the area of the rectangle then the area of the triangle. Then when you find both areas of the two shapes add them up to get the area of the arrow. If you don't know how to find the area of those two shapes you are so far lost.
A rectangle and triangle have equal areas the length of the rectangle is 12 in and its width is 8 in if the base of the triangle is 32 in what is the length in inches of the altitude drawn to the base?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches altitude drwn to ba?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altitu?
6
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altitude dra?
6
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altiitude dr?
6 inches
A rectangle and triangle have equal areas - the rectangle's length is 12 inches and its width is 8 inches so if the base of the triangle is 32 inches what is the length in inches of the altitude drawn?
The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altit?
Area of rectangle = l x w: 12 x 8 = 96 sq in Area of triangle is bh/2: 96 = 32(h)/2 192 = 32(h) 6 = h The heigth of the triangle is 6 inches
A rectangle and triangle have equal areas The rectangle is 12 inches long and 8 inches wide If the base of the triangle is 32 inches what is the length in inches of the altitude drawn to the base?
Area Rectangle = 12 * 8 = 96 sq. in.Area Triangle = 1/2 base * height -> 96 = 16 * height -> 96 / 16 = height = 6 in.
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the?
The formula for the area (R) of a rectangle is R = length x width = 12 x 8 = 96 sq in.The formula for the area (T) of a triangle is T = 1/2 base x altitude (a)(or vertical height) Then 96 = 1/2 x 32 x a : 96 = 16a : therefore a = 6 inches.Answer : The altitude of the triangle = 6 inches
A rectangle and a triangle have equal areas If the rectangle has a length of 12 inches and a width of 8 inches and the base of the triangle is 32 inches what is the length of altitude drawn to base?
Area of the rectangle = (Length x Width) = (12 x 8) = 96Area of the triangle = 1/2 (Base x Altitude) = 1/2 (32 x Alt) = also 96 1/2 (32 x Alt) = 96 32 x Alt = 192 Alt = 192/32 = 6 inches
A rectangle and triangle have equal areas. The rectangle is 12 inches long and 8 inches wide. If the base of the triangle is 32 inches what is the length in inches of the altitude drawn to the base?
The altitude will be 6 inches in length. The area of the rectangle is length (l) times width (w) or l x w = 12 x 8 = 96 The area of a triangle is 1/2 the base (b) times the height (h), or altitude, and, because the area of the triangle is equal to the area of the rectangle, both will have an area of 96. For the triangle, 1/2 b x h = 1/2 x 32 x h = 96, and 16 x h = 96, and h = 6
How do you find the area of the shaded part of a rectangle that is 12 inches by 9 inches that has a lopsided triangle non shaded in the center?
You either need to find the area of the triangle and subtract it from that of the rectangle OR you find the areas of the bits of the rectangle that are outside the triangle and add them together. Without more details of the triangle, it is not possible to give a more detailed answer.
