A rectangle 6.3 inches long and 12.2 inches high has an area of 76.86 inches.
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
Add the length and the width; Double the answer; Job done.
Area of rectangle = Length * Breadth 126 = 18 * B => B = 126/18 = 7 inches.
24
Using Pythagoras' theorem it is 26 inches in length
A rectangle 6.3 inches long and 12.2 inches high has an area of 76.86 inches.
It would be 15 inches long.
The area of rectangle is : 30.0
it's four thirds as long as it is wide.
The area of rectangle is : 21.0
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
Add the length and the width; Double the answer; Job done.
To find the area of a rectangle (or the product of its length and width), you can simply multiply the length by the width. In this case: Area = Length × Width Area=Length×Width Area = 39 inches × 47 inches Area=39inches×47inches Area = 1833 square inches Area=1833square inches So, the area of a rectangle with dimensions 39 inches by 47 inches is 1833 1833 square inches.
Invalid conversion: square inches is a measure of area and inches is a measure of length or distance.If each side of a square is 10 inches long, the area of the square will be 100 square inches. (10*10=100)For any rectangle with an area of 100 square inches, the length of the short side times the length of the long side must total 100.(For instance, a rectangle 4 inches by 25 inches: 4*25=100)
15 inches (solved with the help of Pythagoras' theorem)
If the length is 15.5 feet then the combined length of the two long sides is 31 feet, this leaves 9 feet, which divided between the two shorter sides means each must be 4.5 feet long or 4 feet 6 inches long if you prefer.