36 cm is the perimeter of the rectangle.
Since it is the perimeter, there will be two long sides and two short sides. , making the four sides.
This can be algebraically expressed as
P = 2(l + s)
P = 2l + 2s
Substituting
P = 36 sm
s = 4 cm ( assumed).
36 cm = 2l + 2(4cm)
36 cm = 2l + 8 cm
2l = 36 cm - 8cm ( Note the change of sign , when 'crossing the '=' sign
2l = 28 cm
Divide both sides by '2'
l = 14 cm ( is the length).
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
The length is (18 centimeters) minus (the width)
3 cm
Length 17 cm. Width 10 cm.
77cm!
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
The length is (18 centimeters) minus (the width)
In a rectangle, the area is calculated by multiplying length x width. If (for example) both length and width are in centimeters, the area will be in square centimeters.
30 ft
150 cm !
46 centimeters
3 cm
21cm3
Length 17 cm. Width 10 cm.
77cm!
If the area of a rectangle is found by measuring the length times the width, then if you know the area is 256 and the width is 8, you find the length by dividing 256 by 8 which would give you a length of 32 centimeters.
6cm. The perimeter of the rectangle has to add to 20. 4+4+6+6=20 Hope this helps ;-)