No.
Suppose bi and di are two complex purely imaginary numbers such that b and d are real.
Then
bi * di = bdi2 = -bd which is real.
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A complex number has a real part and a (purely) imaginary part, So imaginary numbers are a subset of complex numbers. But the converse is not true. A real number is also a member of the complex domain but it is not an imaginary number.
The only thing I can think of that you might mean is an imaginary or complex number. Since there is no solution to √(-1) mathematicians labeled it as i which is the imaginary number, and any number that includes purely i is also imaginary. Complex numbers are a mix of both real and imaginary numbers. for example 3 is real, 5i is imaginary and 3+5i is complex. Hopefully this answers what you meant.
An imaginary number is a square root of a negative number. Imaginary numbers have the form bi where b is a non-zero (real number) and i is the imaginary unit, defined as the square root of − 1.if we define 'imaginary numbers' as 'complex numbers having a real part as 'zero' and a non-zero imaginary part'.. 0 doesn't fit in this description. But by, convention and for theoretical symmetry , we'll have to define 'real numbers' in pretty much the same way, and hence 0 would neither be a purely imaginary number or a purely real number.Overall i would say that 0 is a real number. Imaginary numbers only involve square roots of negative numbers.http://wiki.answers.com/Is_the_zero_imaginary_number#ixzz16w9viQWx
Yes, I can't think of any way that a real number minus another real number would be complex or purely imaginary. My answer is yes.
There are no rational numbers between sqrt(-26) and sqrt(-15). The interval comprises purely imaginary numbers.