A complex number has a real part and a (purely) imaginary part, So imaginary numbers are a subset of complex numbers. But the converse is not true. A real number is also a member of the complex domain but it is not an imaginary number.
The only thing I can think of that you might mean is an imaginary or complex number. Since there is no solution to √(-1) mathematicians labeled it as i which is the imaginary number, and any number that includes purely i is also imaginary. Complex numbers are a mix of both real and imaginary numbers. for example 3 is real, 5i is imaginary and 3+5i is complex. Hopefully this answers what you meant.
An imaginary number is a square root of a negative number. Imaginary numbers have the form bi where b is a non-zero (real number) and i is the imaginary unit, defined as the square root of − 1.if we define 'imaginary numbers' as 'complex numbers having a real part as 'zero' and a non-zero imaginary part'.. 0 doesn't fit in this description. But by, convention and for theoretical symmetry , we'll have to define 'real numbers' in pretty much the same way, and hence 0 would neither be a purely imaginary number or a purely real number.Overall i would say that 0 is a real number. Imaginary numbers only involve square roots of negative numbers.http://wiki.answers.com/Is_the_zero_imaginary_number#ixzz16w9viQWx
Yes, I can't think of any way that a real number minus another real number would be complex or purely imaginary. My answer is yes.
There are no rational numbers between sqrt(-26) and sqrt(-15). The interval comprises purely imaginary numbers.
A complex number has a real part and a (purely) imaginary part, So imaginary numbers are a subset of complex numbers. But the converse is not true. A real number is also a member of the complex domain but it is not an imaginary number.
The only thing I can think of that you might mean is an imaginary or complex number. Since there is no solution to √(-1) mathematicians labeled it as i which is the imaginary number, and any number that includes purely i is also imaginary. Complex numbers are a mix of both real and imaginary numbers. for example 3 is real, 5i is imaginary and 3+5i is complex. Hopefully this answers what you meant.
A complex number is any number that is in the real/imaginary plane; this includes pure reals and pure imaginaries. The difference between two numbers inside this plane is never outside this plane; therefore, yes, the difference between two complex numbers is always a complex number. However, the difference between two numbers that are neither purely imaginary nor purely real is not always necessarily a number that is neither purely imaginary nor purely real. Take x+yi and z+yi for instance, where x, y, and z are all real: (x+yi)-(z+yi)=x+yi-z-yi=x-z. Since x and z are both real numbers, x-z is a real number.
An imaginary number is a square root of a negative number. Imaginary numbers have the form bi where b is a non-zero (real number) and i is the imaginary unit, defined as the square root of − 1.if we define 'imaginary numbers' as 'complex numbers having a real part as 'zero' and a non-zero imaginary part'.. 0 doesn't fit in this description. But by, convention and for theoretical symmetry , we'll have to define 'real numbers' in pretty much the same way, and hence 0 would neither be a purely imaginary number or a purely real number.Overall i would say that 0 is a real number. Imaginary numbers only involve square roots of negative numbers.http://wiki.answers.com/Is_the_zero_imaginary_number#ixzz16w9viQWx
Yes, the only argument would be the example, i + (-i) = 0. However, many people don't realize that 0 is both a purely real and pure imaginary number since it lies on both axes of the complex plane.
Yes, I can't think of any way that a real number minus another real number would be complex or purely imaginary. My answer is yes.
i34 is the complex part of the number 0+i34. The real part is 0, so this is a purely imaginary number.
They can be either. If they are roots of a real polynomial then purely imaginary would be symmetric and only real roots can be skew symmetric.
There are no rational numbers between sqrt(-26) and sqrt(-15). The interval comprises purely imaginary numbers.
No. It's purely imaginary.
There is no specific term for such polynomials. They may be referred to as are polynomials with only purely complex roots.
Skew-Hermitian matrix defined:If the conjugate transpose, A†, of a square matrix, A, is equal to its negative, -A, then A is a skew-Hermitian matrix.Notes:1. The main diagonal elements of a skew-Hermitian matrix must be purely imaginary, including zero.2. The cross elements of a skew-Hermitian matrix are complex numbers having equal imaginary part values, and equal-in-magnitude-but-opposite-in-sign real parts.