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An imaginary number is a square root of a negative number. Imaginary numbers have the form bi where b is a non-zero (real number) and i is the imaginary unit, defined as the square root of − 1.
if we define 'imaginary numbers' as 'complex numbers having a real part as 'zero' and a non-zero imaginary part'.. 0 doesn't fit in this description. But by, convention and for theoretical symmetry , we'll have to define 'real numbers' in pretty much the same way, and hence 0 would neither be a purely imaginary number or a purely real number.
Overall i would say that 0 is a real number. Imaginary numbers only involve square roots of negative numbers.
http://wiki.answers.com/Is_the_zero_imaginary_number#ixzz16w9viQWx
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Does dividing by zero result in an imaginary number?
No. Dividing by zero is undefined. It does not result in anything.
Is 0 an imaginary number?
This is an interesting question. Looking at complex numbers graphically, zero is at the intersection of the real and imaginary axis, so it is 0 + 0i. But if you square zero, you get zero, which is not a negative number (a pure imaginary, when squared will give a real negative number), so I'd have to say it is not imaginary.
Is every complex number a pure imaginary number?
No. For example the number 1+i. Pure imaginary complex numbers are of the form 0 + a*i, where a is a non-zero real number.
What best describes an imaginary number?
You can describe it as a number defined such that i squared = -1.You can also define the complex plane first, and then describe an imaginary number as a complex number in which the real part is zero.
Is 5192716162 a real number?
Real numbers are the subset of complex numbers with the property that their imaginary part is zero. Since the above number has no imaginary part, it is a real number.
